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2 years ago

13

Prove that for all intergers n≥1, P(n,n)= P(n,(n-1)).

1 answer:

NeX [460]2 years ago

6 0

Answer:amamsjhshsbdbd

Step-by-step explanation:

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EASY!!!! Answer this question correctly

Lesechka [4]

Answer:

1st answer choice- You do not have enough jars because 20 jars will only hold 35 cups of applesauce.

Step-by-step explanation:

So 1.75 cups of applesauce fits in a jar. You have 20 jars so you multiply the cups of applesauce that can fit in the jar by how many jars you have. It will look like this: 1.75x20=? Now you multiply them and you get 35 which is how many cups of applesauce 20 jars will hold. You will have 5 cups of applesauce left over that cannot be transformed into a jar.

If you can please make my answer the brainliest that would be much appreciated. Thanks!

6 0

3 years ago

Read 2 more answers

The mass, m, of an object varies directly as the cube of its length, I.

steposvetlana [31]

Answer:

m = 686.

Step-by-step explanation:

Direct variation :

m= kl^3 where k is a constant.

m = 250 when l = 5, so

250 = k *(5)^3

k = 250 / 125 = 2

So the equation of variation is m = 2l^3.

When l = 7:

m = 2 * (7)*3

= 2 * 343

= 686.

6 0

3 years ago

Read 2 more answers

Four out of every six dental patients request fluoride treatment after their dental cleaning treatments. If 120 patients have de

Orlov [11]

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4 0

3 years ago

You bought a bag of tamales and one of your friends ate 1/5 of the entire bag and another friend ate 1/3 of the whole bag. How m

Serggg [28]

Answer:

There is 7/15 left in the bag

Step-by-step explanation:

So, you need to find a common denominator between 3 and 5 which is 15

multiply the numerator and the denominator by 3 in 1/5. Then, multiply the numerator and the denominator by 5 in 1/3.

1/3*5=5/15

1/5*3=3/15

Add them together.

5/15+3/15=8/15

Lastly, subtract 15/15 by 8/15

15/15-8/15=7/15

3 0

3 years ago

Help please<3 for all questions with solutions plz

antiseptic1488 [7]

Answer:

a) $h = -\frac{7}{4}$ , b) $h = f\,\circ\,g (-5) = \frac{3}{2}$ , c) $h = g\,\circ\,f (-2) = \frac{3}{8}$

Step-by-step explanation:

We proceed to solve each exercise below:

a) $f(-2) +3\cdot g(0)$

$h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)$

$h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)$

$h = -4+\frac{9}{4}$

$h = \frac{-16+9}{4}$

$h = -\frac{7}{4}$

b) $h = f\,\circ \,g (-5)$

$h = f\,\circ\,g (x) = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }$

$h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }$

$h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}$

$h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}$

$h = f\,\circ\,g (-5) = \frac{3}{2}$

c) $h = g\,\circ\,f(-2)$

$h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4 }$

$h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }$

$h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}$

$h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}$

$h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}$

$h = g\,\circ\,f (-2) = \frac{-3}{-8}$

$h = g\,\circ\,f (-2) = \frac{3}{8}$

6 0

3 years ago