Question

The quotient of the square of a number minus the cubed root of another number and the sum of those two numbers is nine. how can this relationship best be stated algebraically

Answer 1

Answer:

$\frac{x^{2} -\sqrt[3]{y}}{x+y}=9$

Step-by-step explanation:

we know that

The quotient means, divide the numerator by the denominator

In this problem

1) The numerator is "the square of a number minus the cubed root of another number"

Let

x ----> a number

y ----> another number

The algebraic expression of the numerator of the quotient is

$x^{2} -\sqrt[3]{y}$

2) The denominator is "the sum of those two numbers"

so

The algebraic expression of the denominator of the quotient is

$x+y$

3) The quotient of the square of a number minus the cubed root of another number and the sum of those two numbers is nine

Equate the quotient to the number 9

so

we have

$\frac{x^{2} -\sqrt[3]{y}}{x+y}=9$