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Vesna [10]
3 years ago
5

Malika responded that the value of t in the equation, t3 = 64/27 is 8/3. Explain why you agree or disagree with Malika. Justify

your answer by showing how you arrived at your value for t.
Mathematics
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

divide 64/8 and 27/9 to arrive at 8/3 for 64/27

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Which subpart(s) of the 45 cfr 46 is/are sometimes referred to as the common rule?
Olenka [21]

Subpart a is the subpart of the 45 CFR 46 which describes the required protections for all human subjects.

 

The application of the federal policy regarding Human Subjects Protection to 17 Federal agencies and offices is called the Common Rule. Federal agencies that did not sign the agreement (e.g., Department of Labor, etc.) are exempted from the policy. The Common Rule’s main elements include the following:

 

<span>1.     </span>research institutions’ requirements for assuring compliance

<span>2.     </span>obtaining and documenting informed consent requirements for researchers'

<span>3.     </span>Institutional Review Board (IRB) membership, operations, function, record keeping, and review of research requirements

 

 

The specific vulnerable research subjects’ additional protections are included in the Common Rule.

 

 

<span>Additional protections for pregnant women, in vitro fertilization, and fetuses is provided in subpart B.

Additional protections for prisoners is contained in subpart C.</span>

<span>
The same for children is contained in subpart D.</span>

8 0
3 years ago
the length of a rectangle is 8in. more than it’s width. the perimeter of the rectangle is 24in. what are the width and length of
igomit [66]
The width is 2 in., and the with is 8 in.
4 0
3 years ago
Simplify (1234567)^0
Daniel [21]

Answer:

every \: number \: by \: power \: 0 \: is \: equal1 \\  {x}^{0}  = 1

4 0
3 years ago
Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators
Nata [24]

Answer:

The solution is y=-\frac{12}{12x-30x^2+1}.

Step-by-step explanation:

A first order differential equation y'=f(x,y) is called a separable equation if the function f(x,y) can be factored into the product of two functions of x and y:

f(x,y)=p(x)h(y)

where p(x) and h(y) are continuous functions.

We have the following differential equation

y'=(1-5x)y^2, \quad y(0)=-12

In the given case p(x)=1-5x and h(y)=y^2.

We divide the equation by h(y) and move dx to the right side:

\frac{1}{y^2}dy\:=(1-5x)dx

Next, integrate both sides:

\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C

Now, we solve for y

-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}

We use the initial condition y(0)=-12 to find the value of C.

-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}

Therefore,

y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}

4 0
3 years ago
If f(x)=6x-4, what is f(x) when x = 8
gtnhenbr [62]
F(x)= 6x-4
f(x)=6*8-4
f(x)=48-4
f(x)=44
3 0
3 years ago
Read 2 more answers
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