Answer:
Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".
Step-by-step explanation:
Since the object has a initial velocity and it's being accelerated by gravity, than it's height is defined by:
H(t) = H(0) + V(0)*t + 0.5*g*t²
Applying the data from the problem, we have:
H(t) = 15 + 8.5*t + 0.5*32.17405*t²
H(t) = 15 + 8.5*t + 16.09*t²
Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".
Step-by-step explanation:
1/2 × height × base
1/2 × 6.3 × 8
6.3 × 4 = 25.2 ans.
therefore, area of the ∆ is 25.2 ft ².
Answer:
The number he thought of was 13
Step-by-step explanation:
Revers the problem
3.5 * 3 = 10.5
10.5 - 4 = 6.5
6.5 * 2 = 13
The answer is c. 12ac^14/b^3
