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tia_tia [17]
3 years ago
13

Find decimal notation. 66 7/8%

Mathematics
1 answer:
Aliun [14]3 years ago
8 0

The Answer to your problem is:

0.66875

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Explain why the exponents cannot be added in the product 12^3 x<br> 11^3.
sergij07 [2.7K]

Answer:

see explanation

Step-by-step explanation:

The exponents can only be added if the bases are the same

Here one base is 12 and the other is 11

So the rule of addition is not applicable.

4 0
2 years ago
Read 2 more answers
Please help! its due in 10 mins
den301095 [7]

Answer:

144

Step-by-step explanation:

sorry if im wrong its been awhile since ive done this

4 0
3 years ago
Mrs. Kennedy is buying pencils for each of 315 students. The pencils are sold in boxed of tens. How can she use rounding to deci
ExtremeBDS [4]
Mrs.Kennedy can divide 315 by 10 and then when she gets her answer she can round up to get her answer.
3 0
3 years ago
In an examination it is required to get 40% of the aggregate marks to pass. A student gets 261 marks and is declared failed by 4
svetoff [14.1K]
The solution to the problem is as follows:

<span>→x− 4% (x) = 261</span>
<span><span>
→x − <span><span>4x/</span>100 </span>= 261

</span></span>I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

6 0
3 years ago
Read 2 more answers
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