Answer:
216.0cm³ of ore must be processed
Explanation:
First, we need to know how many grams of gold we need to obtain $100.00
<em>Mass of gold to obtain $100.00:</em>
$100.00 gold * (1 troy oz / $818) = 0.122 troy oz
0.122 troy oz * (1.0lb / 14.6troy oz) = 8.37x10⁻³ lb
8.37x10⁻³ lb * (454g / 1lb) =
3.80g of gold we need to obtain $100.00
Now, the ore contain 0.22g of gold in 100g and the density of the ore is 8.0g/cm³. We can solve the cubic centimeters to obtain $100.00:
<em>Cubic centimeters of ore:</em>
3.80g Gold * (100g Ore / 0.22g Gold) = 1727.9g of Ore
1727.9g Ore * (1cm³ / 8.0g Ore) =
<h3>216.0cm³ of ore must be processed</h3>
To determine the amount of heat the block has absorbed, we simply multiply the mass of the block of ice to the heat of fusion of water which is given above. We calculate as follows:
Heat = 20.0 kg (3.34 x 10^5 J/kg)
Heat = 6680000 J
Hope this helped.
Answer:
more reliable. The more results the better results you get.
Explanation:
LiOH ( <span>Lithium hydroxide ) .
hope this helps!</span>