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Vsevolod [243]
3 years ago
8

(03.05 LC) Match the term with its description. (4 points) Column A 1. Acid : Acid 2. Alkaline : Alkaline 3. pH : pH 4. Ion : Io

n Column B a. An atom or molecule that has a positive or negative charge b. A value from 0 to 14 that is used to specify how acidic or basic a compound is when it is dissolved in water c. A compound that increases hydrogen ions (H+) when it is dissolved in a solution d. A compound that increases the hydroxide ions (OH-) when it is dissolved in a solution
Computers and Technology
1 answer:
Nady [450]3 years ago
8 0

Answer:

Follows are the matching to this question:

Explanation:

Column  A            Column B

     1                           c

     2                          d

     3                          b

     4                          a

Description of the matching:

  • In 1(Acid) the correct choice is (c) because the acid (HCl) dissociates to both the H+ ion and the Cl- ion as a solution.  
  • In 2(Alkaline ) the correct choice is (d) because alkaline NaOH is a solution that differentiates between the ions ( OH-) and Na+.  
  • In 3(pH ) the correct choice is (b) because for an A compound of less than 7 is an acid and an alkaline pH compound of more than 7. For neutral compounds, a pH of 7 is applicable.
  • In 4(Ion) the correct choice is (a) because Na+ ion is loaded positive, and Cl-ion is loaded negatively.
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A. Calculate the diffusion coefficient for magnesium in aluminum at 450°C.
SIZIF [17.4K]

Answer:

a) D = 4.88 * 10^(-14) m^2 / s

b)   <em>t </em>= 1.1 hr

Solution:

a) Magnesium in Aluminum diffusion:

D = Do * exp(-Qd / RT)

  =  (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)

  = 4.88 * 10^(-14) m^2 / s

D = 4.88 * 10^(-14) m^2 / s

b) The composition remains same at say the distance Xo:

(Cx - Co) / (Cs - Co) = Constant

Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15

D_{550} * <em>t </em>= D_{450} * 15

(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>

(4.88 * 10^(-14) m^2 / s) * 15

by, solving for <em>t </em>we get:

 <em>t </em>= 1.1 hr

So, the time required is 1.1 hr.

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python A pet shop wants to give a discount to its clients if they buy one or more pets. The discount is equal to 20 percent of t
Artyom0805 [142]

Answer:

The following are the program in the Python Programming Language.

#define function

def discount(prices, isPet, nItems):

 # declare and initialize variables to 0

 i = 0

 cost = 0

 pets = 0

 item = 0

 item_Cost = 0

 #set the while loop

 while(i < nItems):

   #check the items of the variable

   if isPet[i]:

     #add and initialize in the cost

     cost += prices[i]

     #increament in the variable by 1

     pets += 1

   #otherwise

   else:

     #add and initialize in the item_Cost

     item_Cost += prices[i]

     #increament in the variable by 1

     item += 1

   #then increment in the variable by 1

   i += 1

 #check the pet is greater than equal to 1  

 #and item is greater than equal to 5

 if(pets >= 1 and item >=5):

   #then, print the message

   print("You receive discount")

   #set discount of the items

   discount = 0.2 * item_Cost

   # calculate bill after deducting discount

   bill = cost + item_Cost - discount

   #print the bill

   print("Final Bill amount is", bill)

 #otherwise

 else:

   #print the message

   print("You do not receive any discount")

   #calculate bill without deducting discount

   bill = cost + item_Cost

   #print the final bill

   print("Final Bill amount is", bill)

#set empty list type variables

price = []

pet = []

#set the infinite loop

while True:

 #get input from the user

 sprice = int(input("Enter the price (-1 to quit): "))

 #check that price is not equal to the -1

 if(sprice != -1):

   #add price in the list

   price.append(sprice)

   #ask for choice from the user

   choice = input("Is it a pet (Y / N)? ")

   #check the choice of the user is y or Y

   if(choice == 'Y' or choice == 'y'):

     # then, add in the pet

     pet.append(True)

   #otherwise

   else:

     #not add in the pet

     pet.append(False)

   print("")

 #break the loop

 else:

   break

#declare variable that store the length

items = len(price)

#call and initialize the variable

discount(price, pet, items)

<u>Output</u>:

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? y

Enter the price (-1 to quit): 69

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 41

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 52

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 74

Is it a pet (Y / N)? n

Enter the price (-1 to quit): -1

You receive discount

Final Bill amount is 361.6

Explanation:

<u>The following are the description of the program</u>.

  • Firstly, define the function 'discount()' and pass the arguments 'prices', 'isPet' and 'nItems' in its parameter.
  • Then, declare and initialize the variables 'i' to 0, 'item_Cost' to 0
  • , item to 0, 'cost' to 0 and 'pets' to 0.
  • Then, set the while loop to add the price of the items and the cost of the pets.
  • Set the if-else conditional statement to check the pet is greater than equal to 1 and the items are greater than equal to 5 then, set the discount and print the bill after deduction.
  • Otherwise, print the bill without deduction.
  • Finally, set two list type variable then, set the infinite while loop that gets input from the user and check that the variable is not equal to -1 then append the data in the list then again check the user input then append in pet otherwise not append in pet and break the loop. Then, set the variable that stores the length of the price and call the following function by passing arguments in its parameter.
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3 years ago
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