Kenny is asked to submit a photo for the annual photographic competition. He decided to capture a photo with the light-painting
1 answer:
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Answer:
Check the explanation
Explanation:
1) supposing the keystream is a stream that is of random bits in Z26, we can describe a stream cipher based on the Latin Alphabet that is as follows (where A ↔ 0, B ↔ 1, C ↔ 2 etc):
mod26
mod26
2)
= ” B ” − ” R ” = 1 − 17 = − 16 ≡ 10 mod 26 = ” K ” etc ·
The Decrypted Text is: ”KASPAR HAUSER”
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
int main()//main method
{
int c= 0;//defining integer variable to count number of solutions
int x,y,z;//defining integer variable which is used in the loop
for (x = 0; x <= 100; x++)//defining for loop to x value
for (y = 0; y <= 100; y++)//defining for loop to y value
for (z = 0; z <= 100; z++)//defining for loop to z value
if (4 * x + 3 * y - 9 * z == 5)//use if to check given condition
{
c++;//increment count value
cout << "(" << x << "," << y << "," << z << ")";//print solutions
cout << (c % 11? " " : "\n");//use for add file solution in a row
}
cout << "\n\nThere are " << c << " solution(s)\n";//print solution couts
return 0;
}
Output:
Please find the attached file.
Explanation:
In the above-given code four integer variable "x,y,z, and c" is declared, in which "x,y, and z" is used in the for loop with the if conditional statement that checks the given condition and prints the solution and the "c" variable is used to counts the number of solution, and at the last, it uses the print method to print its values.
