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Zielflug [23.3K]
3 years ago
7

Please. You can help me with this problem. Thanks.

Mathematics
2 answers:
Sergio [31]3 years ago
5 0
That would be 23! answer B
Anarel [89]3 years ago
4 0

Answer:

there is no question so no need to thank me

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Flying against the wind, an airplane travels 3760 kilometers in 4 hours. Flying with the wind, the same plane travels 4320 kilom
Gemiola [76]

Answer:

1 hour each 30 minutes so the answer is 30 minutes

5 0
3 years ago
What is the length of the base of a yield sign that has a height of 14 inches and has an area of 84 square inches? Write the num
Rufina [12.5K]
That's simple, it is 6. Hope this helps.
4 0
4 years ago
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Solve for x 5x - 5 = 5
Viktor [21]

Polynomial equation solver

5x - 5 = 5

Standard form:

5x − 10 = 0

Factorization:

5(x − 2) = 0

Solutions:

x = 10

5

= 2

7 0
3 years ago
Pls help if pls do most important 15 number 20 number 26 number 28 number 30 number 17 number 25 number 22 number 24 number if u
Tamiku [17]

Answer:

Step-by-step explanation:

15. \frac{cotx+1}{cotx-1} = \frac{cotx+cotx.tanx}{cotx-cotx.tanx} = \frac{cotx(1+tanx)}{cotx(1-tanx)} = \frac{1+tanx}{1-tanx}   \\

16.  \frac{1+cos\alpha }{sin\alpha } = \frac{sin\alpha }{1-cos\alpha }

=> (1+cos\alpha )(1-cos\alpha ) = sin^{2} \alpha \\=> 1-cos^{2}\alpha =sin^{2}  \alpha \\=> sin^{2}\alpha +cos^{2}\alpha =1\\

=> The clause is correct

17. Do the same (16)

18. \frac{sinx}{1-cosx}+\frac{sinx}{1+cosx} = \frac{sinx(1+cosx) + sinx(1-cosx)}{(1+cosx)(1-cosx)} = \frac{sinx + sinx.cosx + sinx - sinx.cosx}{1-cos^{2}x} = \frac{2sinx}{sin^{2}x }= \frac{2}{sinx} = 2cosecx

19.

\frac{sinA}{1+cosA} + \frac{1+cosA}{sinA}=\frac{2}{sinA} \\=> \frac{sinA}{1+cosA} + \frac{1+cosA}{sinA} - \frac{2}{sinA} \\ = 0\\=> \frac{sinA}{1+cosA} + (\frac{1+cosA}{sinA} - \frac{2}{sinA} \\) = 0\\=> \frac{sinA}{1+cosA} + \frac{1+cosA-2}{sinA} = 0\\=> \frac{sinA}{1+cosA} +\frac{cosA-1}{sinA} = 0\\=> \frac{sin^{2} A+(cosA-1)(1+cosA)}{(1+cosA)sinA}=0\\=> \frac{sin^{2} A+cos^{2} A-1}{(1+cosA)sinA}=0\\=> \frac{0}{(1+cosA)sinA} =0\\

=> The clause is correct

20. Do the same (18)

21. Left = \frac{1}{cosecA+cotA} = \frac{1}{\frac{1}{sinA}+\frac{cosA}{sinA}  } = \frac{1}{\frac{1+cosA}{sinA} }= \frac{sinA}{1+cosA}

Right = cosecA-cotA = \frac{1}{sinA}-\frac{cosA}{sinA}= \frac{1-cosA}{sinA}   \\

Same with (16) => Left = Right => The clause is correct

22. Do the same (21)

Too long, i'm so lazy :))))

5 0
3 years ago
Can you help me. What is 2x-14
mylen [45]

Answer: 2(x-7)

Step-by-step explanation: 2x−14

2x−14

=2(x−7)

4 0
3 years ago
Read 2 more answers
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