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3 years ago

Hmm it would have seem that I'm in need of help here help with this

Mathematics

1 answer:

inn [45]3 years ago

5 0

To find out the answer,we can test it out one by one:

The original expression: 6×(2+8)=60

A. 6x(8+2)= 6x10 = 60✅

B. (6×2)+8 = 24+8 = 34

C. (8+2)x6 = 10×6 = 60✅

D. 6x2÷6×8 =12÷6×8 = 2×8 = 16

As A. and C. equals to the original expression, the answer is A. and C.

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I’m begging you too pls pls pls pls help! I’d appreciate it so much. This is independent work and I have no clue of what this me

lions [1.4K]

Answer:

1. 160 min

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3 years ago

Suppose x=9 tan (theta) and the angle (theta) is in the first quadrant. Write algebraic expressions for sin (theta) and cos (the

9966 [12]

The tangent trigonometric function is equal to the quotient of sine and cosine through the trigonometric identity. In this case, we are given with x = 9 tan (theta). Hence the answer to this problem is the expounded algebraic expression x = 9 sin (theta) / cos (theta).

3 0

3 years ago

Hep yep help helphelp

iragen [17]

Answer:

pretty sure it's A

Step-by-step explanation:

cuz a common factor of 9 and 10 is 90 do the calculations and it should be simple.

6 0

3 years ago

Part D

Assoli18 [71]

Answer:

BD and BE are tangents to the circle

Step-by-step explanation:

Given

See attachment

Required

What does BD and BE represent?

From the attachment, we have:

$\angle BDA = 90^\circ$

$\angle BEA = 90^\circ$

$Radii = AD\ and\ AE$

The measure of angles between a tangent and the radius of a circle is always $90^\circ\\$

So, because $\angle BDA = 90^\circ$ and AD is a radius, then BD is a tangent to circle.

Similarly,; $\angle BEA = 90^\circ$ and AE being a radius implies that BE is a tangent to circle.

4 0

3 years ago

Question 11

SpyIntel [72]

Answer:

The value of x for the given transversal line t and parallel lines w , v is 17

Step-by-step explanation:

Given as :

The two parallel lines are w and v

The tow parallel lines are transversal intersecting by another line t at two points as show

Let The angle made by transversal when intersecting the line w is ∠a

And The angle made by transversal when intersecting the line v is ∠b

∵ line w ║ line v

∴ ∠a = ∠b ( corresponding lines axiom )

<u>So, from figure</u>

(4 x - 3)° = 65°

Or, 4 x = 65° + 3°

Or, 4 x = 68°

∴ x = $\frac{68^{\circ}}{4^{\circ}}$

I.e x = 17

So, The value of x = 17

Hence The value of x for the given transversal line t and parallel lines w , v is 17 . Answer

8 0

4 years ago