Answer:
A function f:R→R is periodic if there exists some number t>0 such that
f(x)=f(x+t)
A constant function is periodic since you can take t=1,t=2, etc. (Hint: Hover over the tag "periodic-functions". What do you see?)
The fundamental period of f is the smallest of such t's. Since t cannot be 0, you are looking for the minimum of (0,∞), which does not exist.
Step-by-step explanation:
Answer:
42
Step-by-step explanation:
Answer: 9x^2 - 6x + 8
Step-by-step explanation:
(9x^2 - 2x + 7) - (4x - 1) Subtract like terms
The term 9x^2 doesn't have any other term so it will stay alone.
-2x - 4x = - 6x
7 - (-1) = 8
Put them together to get 9x^2 - 6x + 8
Plug it into point-slope form.
y - y1 = m(x - x1)
Where y1 is the y-value of the point, x1 is the x-value, and 'm' is the slope.
So plug in -1 for x1, 2 for y1, and 0.9 for 'm':
y - 2 = 0.9(x + 1)
Simplify to get in slope-intercept form:
Distribute 0.9 into the parenthesis:
y - 2 = 0.9x + 0.9
Add 2 to both sides:
y = 0.9x + 2.9
