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myrzilka [38]
3 years ago
6

Kevin and randy muise have a jar containing 87 ​coins, all of which are either quarters or nickels. the total value of the coins

in the jar is ​$12.55. how many of each type of coin do they​ have?
Mathematics
1 answer:
boyakko [2]3 years ago
4 0
Let x be the amount of nickels and y be the amount of quarters in a jar. Totally there are 87 coins, then x+y=87.

Since nickel is 5 cent coin and quarter is 25 cent coin, then 5x+25y=1255 ($12.55=1255 cents). Solve this system:x=87-y and 5(87-y)+25y=1255.
435-5y+25y=1255,
25y-5y=1255-435,

20y=820,
y=820÷20,
y=41,
x=87-41=46.
Answer: 46 nickels and 41 quarters.

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Sergio039 [100]
The ratio of Isabella’s money to Shane’s money is 3:11

Isabella has $33.   

We can make a proportion to solve for how much money Shane has.   
A proportion is two ratios that are set equal to each other.  

Let’s call Shane’s money ‘S’   

We get this proportion:   3/11 = 33/x   

If we cross multiply we get:   
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Simplifying it, we get:
363 = (3) * (x)   

Divide both sides by 3, we get:
x = 121   

However, the question asks how much money they have together. 

Isabella + Shane = Total
33 + 121 = $154   

<span>They have $154 together.</span>
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