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MrRa [10]
3 years ago
8

A rectangular garden is 15 ft longer than it is wide. Its area is 700 ft. What are its dimensions?

Mathematics
2 answers:
ipn [44]3 years ago
8 0
20ft and 35ft are the dimensions
NARA [144]3 years ago
7 0

Step-by-step explanation:

<u>Given</u><u> </u><u>:</u><u>-</u><u> </u>

  • The length of rectangular garden is 15 feet longer than its width
  • The area of rectangular garden is 700ft²

<u>To </u><u>find</u><u>:</u><u>-</u>

  • Dimensions of rectangular garden

<u>Solution</u><u>:</u><u>-</u>

According to the question , let the length of rectangular garden be x and width be x + 15

<u>We know ,</u> the formula for area of rectangular garden is <u>L × B</u>

putting the known values ,

700ft.² = X × (X + 15)

700 ft. ² = x² + 15x

x² + 15 x - 700 = 0

<u>By </u><u>factorising</u><u> </u><u>it </u><u>we </u><u>get</u><u> </u><u>,</u><u> </u>x = 20

So , the dimensions of rectangular garden are 20 feet and 35 feet respectively for length and width.

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35 ten thousands,8 hundreds is greater than or less than 3 hundred thousands 50 thousands, 80 tens ?
enot [183]

35 ten thousands,8 hundreds is greater..I think

Step-by-step explanation:

35 ten thousands,8 hundreds =350,000,800

3 hundred thousands 50 thousands, 80 tens =350,000,080

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If sin theta = 1/2 and pi/2 &lt; theta &lt; pi , what are the values of cos and tan?
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Answer:

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Step-by-step explanation:

Referring to the attached short table of trig functions, we see that the reference angle with sin(θ) = 1/2 is π/6. The table also shows cosine and tangent values for that angle.

In the second quadrant, where π/2 < θ < π, the cosine and tangent are both negative. The values you seek are ...

  cos(θ) = -(√3)/2

  tan(θ) = -1/√3 = -(√3)/3

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3 years ago
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Step-by-step explanation:

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a coin is tossed and an eight sided die numbered 1 through 8 is rolled. find the probability of tossing a head and then rolling
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Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r
Masteriza [31]
Part A)

f(x) = 5^x
f(0) = 5^0
f(0) = 1
----------
f(x) = 5^x
f(1) = 5^1
f(1) = 5
----------
f(x) = 5^x
f(2) = 5^2
f(2) = 5*5
f(2) = 25
----------
f(x) = 5^x
f(3) = 5^3
f(3) = 5*5*5
f(3) = 125

-------------------

Rate of change for section A = (f(1) - f(0))/(1 - 0)
Rate of change for section A = (5 - 1)/(1 - 0)
Rate of change for section A = 4/1
Rate of change for section A = 4

Rate of change for section B = (f(3) - f(2))/(3 - 2)
Rate of change for section B = (125 - 25)/(3 - 2)
Rate of change for section B = 100/1
Rate of change for section B = 100

================================================

Part B)

From part A) above, we found,

Rate of change for section A = 4
Rate of change for section B = 100

Which means that section B's rate of change is 25 times greater (since 100/4 = 25, or 25*4 = 100)

Answer for part B: 25

================================================

Extra:  Explain why one rate of change is greater than the other.

The rate of change for section B is larger because the exponential function is growing faster as x increases. This is shown visually by the sharper and steeper incline as the function curve goes upward. The function starts off with relatively slower growth but it accelerates in speed. 

6 0
3 years ago
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