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solmaris [256]
3 years ago
11

3x + 2y = 4

Mathematics
1 answer:
arlik [135]3 years ago
6 0
3x + 2y = 4
2y = -3x + 4
Divide by 2
Solution: y = -3/2x + 2

x + 2y = -4
2y = -x - 4
Divide by 2
Solution: y = -1/2x - 2
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a full container of juice 64 fluid ounces.how many 7 fluid ounces serving of juice are in a full containet?
saul85 [17]
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Hope this helps!

5 0
3 years ago
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Draw Conclusions The decimal 0.3 represents 1. What type of number best describes 0.9, which is 3 0.3? Explain.
liraira [26]
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7 0
3 years ago
Divide 8 in the radio 1:1
Aleksandr [31]
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4 years ago
Can you add and subtract integers and surds together?
Ne4ueva [31]

Answer:

Both of these examples are wrong. You cannot add/subtract integers and square roots together, however, you could add square roots together if they have the same number under the square root. For example, 2 - 2√6 will stay as 2 - 2√6 because they aren't like terms. 25 + 5√5 + 5√5 + 5 = 30 + 10√5 because 25 + 5 = 30 and 5√5 + 5√5 = 10√5. We can add 5√5 and 5√5 together because they have the same number under the square root. If we were to compute √2 + √3, we would just leave it as is because they don't have the same number under the square root.

4 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
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