The answer is no because after each 3 there is one more zero added
to be repeating the number of zeros would have to stay the same
Do you mean an extraneous solution? I will tell you what I think. To tell if a solution is extraneous you need to go back to the original problem and check if there actually is a solution or if the solution is actually right. If not then it is extraneous.
Find the factors from the roots, then multiply the factors together.
y
=
x
2
−
21
x
+
104
It will be 14 we calculated
Answer:
Step-by-step explanation:
ΔABD ≅ ΔCBD .
So AD = DC
8x - 4 = 3x + 1 {add 4 to both sides}
8x = 3x + 1 + 4
8x = 3x + 5 {subtract 3s from both sides}
8x - 3x= 5
5x = 5 {divide both sides by 5}
x = 5/5
x = 1
