Answer:
The area of sector is 7.48 unit²
Step-by-step explanation:
Given as :
The radius of circle = r = 3 unit
The measure of central angle =Ф = radian
Let The area of sector = A unit²
<u>Now, According to question</u>
Area of sector = π× radius × radius ×
Or, A = π× r × r ×
Or, A = π× r × r ×
where π = 3.14
∵ 180° = π radian
So, 360° = = 2 π radian
Or,, A = π× r × r ×
Or, A = π× r × r ×
Or, A = 3.14 × 3 unit × 3 unit ×
Or, A = 3.14 × 3 unit × 3 unit × 0.2647
∴ A = 7.48 unit²
So,The area of sector = A = 7.48 unit²
Hence, The area of sector is 7.48 unit² Answer
Answer:
D. $122.04 in cash and a $206.64 check
Step-by-step explanation:
Answer:
the answer is 4!
Step-by-step explanation:
I took the test in k12
Answer:
C
Step-by-step explanation:
When we set the numerator equal to 0 and solve for x, that value is the horizontal asymptote (a line the graph come towards, but never crosses).
Looking at the graph, the horizontal asymptote is x = 2, so which one of the 4 functions has a horizontal asymptote of 2? Let's check.
A) 2x - 1 = 0
x = 1/2
B) same, x = 1/2
C) 2x -4 = 0
x = 2
D) same as A,B, x = 1/2
As we can see, option C has the right horizontal asymptote and A,B,D are eliminated. So answer is C.
Answer:
Amount of dirt needed to fill the cone = 28.28 in³ (Approx)
Step-by-step explanation:
Given:
Diameter = 6 in
Radius (r) = 6 / 2 = 3 in
Height (h) = 3 in
Find:
Amount of dirt needed to fill the cone
Computation:
Volume of cone = (1/3)πr²h
Volume of cone = (1/3)(22/7)(3)(3)(3)
Volume of cone = 28.28 in³
Amount of dirt needed to fill the cone = 28.28 in³ (Approx)