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3 years ago

8

The cities of los Angeles and new York are located 35 inches apart on a map. If the actual distance between the two cities is 24

50 miles, then what did the scale in the key of the map read

1 answer:

Vsevolod [243]3 years ago

6 0

2450 miles / 35 inches = 70 miles / inch

(big freaking map!)

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Please help me out !

dangina [55]

Answer:

Both -1.5 and -3/2 will be halfway between -2 and -1 on the number line. 3/2 will be halfway between 1 and 2. -4/3 will be between -1.5 and -1.

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3 years ago

Read 2 more answers

What is 4 1/4 -3 3/5

shutvik [7]

First make the denominators the same = 4 5/20 - 3 12/20. Then make them improper fractions= 85/20-72/20= 13/20. Since that is already simplified the answer is 13/20.

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3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

Please help I found this one a bit confusing

Brums [2.3K]

Answer:

7.2

Step-by-step explanation:

To reach point D from point C, you need to add 4 to the x-value of point C and take away 6 from the y-value. These numbers are the sides of the hypothetical triangle.

The Pythagorean Theorem states that $a^2+b^2=c^2$ . If we plug the side lengths in for a and b, we get $4^2 + 6^2 = c^2$ . This can be simplified to $16+36=c^2$ , or $52 = c^2$ . If we root both sides, we find that c is equal to $\sqrt{52}$ , which is slightly more than 7, at around 7.2.

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2 years ago

If a can is 20cm Haigh X 8cm diameter what is the volume

sattari [20]

Radius=8/2=4cm

volume=4*4*3.14*20=1004.8

The answer is 1004.8cm₃

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3 years ago