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irina [24]
3 years ago
11

Solving a right triangle (round to the nearest tenth) ‼️‼️‼️

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 47)° = 180° - 137° = 43°

-------------------------------------------------------------

tan47° = \frac{opposite}{adjacent} = \frac{a}{14}

Multiply both sides by 14

14 × tan47° = a, thus

a ≈ 15.0 (to the nearest tenth )

---------------------------------------------------------------

cos47° = \frac{adjacent}{hypotenuse} = \frac{14}{c}

Multiply both sides by c

c × cos47° = 14 ( divide both sides by cos47° )

c = \frac{14}{cos47} ≈ 20.5 ( to the nearest tenth )

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Step-by-step explanation:

Given

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