Question

Solving a right triangle (round to the nearest tenth) ‼️‼️‼️

Answer 1

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 47)° = 180° - 137° = 43°

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tan47° = $\frac{opposite}{adjacent}$ = $\frac{a}{14}$

Multiply both sides by 14

14 × tan47° = a, thus

a ≈ 15.0 (to the nearest tenth )

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cos47° = $\frac{adjacent}{hypotenuse}$ = $\frac{14}{c}$

Multiply both sides by c

c × cos47° = 14 ( divide both sides by cos47° )

c = $\frac{14}{cos47}$ ≈ 20.5 ( to the nearest tenth )