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WINSTONCH [101]
3 years ago
12

There are 18 skaters competing in the competition. How many ways can they win the gold, silver, and bronze medal?

Mathematics
2 answers:
Len [333]3 years ago
3 0

Only one person can win gold, silver, and bronze. The order of the winner does matter. So it’ll be 18 times 17 times 16.

Alja [10]3 years ago
3 0

Answer: 4,896

Stwhiep-by-step explanation:

Given, There are 18 skaters competing in the competition.

To find : The number of ways in which they can win gold, silver, and bronze medal.

Since, in distribution of medals(gold, silver, and bronze) we require 3 winners in a particular order, so for this we use Permutations.

According to permutation , number of ways of selecting r things out of n = \dfrac{n!}{(n-r)!}

Then, The number of ways in which 18 skaters can win 3 medals= \dfrac{18!}{(18-3)!}=\dfrac{18\times17\times16\times15!}{15!}=4,896

Hence, the required number of ways =4,896

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find the length of the line segment with end points (7,2) and (-4,2) explain how you arrived at your solution
Inga [223]

Answer:

<h2>11 units</h2>

Step-by-step explanation:

Method 1:

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d=\sqrt{(2-2)^2+(-4-7)^2}=\sqrt{0^2+(-11)^2}=\sqrt{11^2}=11

Method 2:

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6 0
3 years ago
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Jeff gave 1/4 of a sum of money to his wife. Then he divided the remainder equally among his 4 children.
Semenov [28]

Answer:

A) The fraction of sum of money did each child receive is \frac{3 x}{16}

B) The sum of money did Jeff have $ 3200

Step-by-step explanation:

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Let The sum of money did Jeff have = $ x

The fraction of money did Jeff's wife get = \frac{1}{4} of $ x

The remaining money Jeff will have = $ x - \frac{1}{4} of $ x

I.e The remaining money Jeff will have = \frac{4 x - x}{4}

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A ) The remaining amount of money is divided equally among 4 children

So, The fraction of sum of money did each child receive = \frac{\frac{3 x}{4}}{4}

I.e The fraction of sum of money did each child receive =  \frac{3 x}{16}

B ) If each child will receive $ 600

∴,  \frac{3 x}{16} = $ 600

Or, 3 x = $ 600 × 16

Or, 3 x = $ 9600

∴    x = \frac{9600}{3}

I.e  x = $ 3200

So, The sum of money did Jeff have $ 3200  

Hence ,

A) The fraction of sum of money did each child receive is \frac{3 x}{16}

B) The sum of money did Jeff have $ 3200   Answer

8 0
3 years ago
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Answer:

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6 0
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