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3 years ago

Solve for x leave answer as decimal 6/5=x/3

Mathematics

2 answers:

777dan777 [17]3 years ago

8 0

Answer:

3 3/5 =x

3 .6 =x

Step-by-step explanation:

6/5 = x/3

Use cross products

6*3 = 5*x

18 = 5x

Divide each side by 5

18/5 = 5x/5

18/5 =x

3 3/5 =x

Dmitrij [34]3 years ago

8 0

Answer: 3.6 = x

Step-by-step explanation: To solve for x in the given proportion, we simply use the means-extremes property which states the the product of the extremes, (6)(3), equals the product of the means, (5)(x).

So we have (6)(3) or 18 equals (5)(x) or 5x.

So we have the equation 18 = 5x.

Now dividing both sides by 5, <em>3.6 = x</em>.

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Vitek1552 [10]

Answer: 5.66666666667

Step-by-step explanation: Thanks and have a Savage day.

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3 years ago

You want to place a towel bar that is 10 1⁄4 inches long in the center of a door that is 26 1⁄3 inches wide. How far should you

Alenkinab [10]

Center of the door

26 1/3 divided by 2

change to an improper fraction

(3*26+1)/3 =79/3

79/3 divided by 2

copy dot flip

79/3 * 1/2

79/6

change to a mixed number

13 1/6

10 1/4 divided by 2

change to an improper fraction (4*10+1)/2 = 41/4

41/4 divided by 2

copy dot flip

41/4 * 1/2 =41/8

change to a mixed number

5 1/8

the left of the bar should be 5 1/8 from the center

to find how far from the left side to place the bar

13 1/6 - 5 1/8 =

get a common denominator

13 4/24 - 5 3/24= 8 1/24 inches

Answer: place the bar 8 1/24 inches from each edge

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3 years ago

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musickatia [10]

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2 years ago

Read 2 more answers

An ion has a charge of +7. How far is it from being neutral?

rusak2 [61]

Answer:

The answer is B. -7

Step-by-step explanation:

the -7 cancels out the +7 which makes it neutral

6 0

3 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago