We can compute the integral directly: we have

Then the integral is



You could also take advantage of Stokes' theorem, which says the line integral of a vector field
along a closed curve
is equal to the surface integral of the curl of
over any surface
that has
as its boundary.
In this case, the underlying field is

which has curl

We can parameterize
by

with
and
.
Note that when viewed from above,
has negative orientation (a particle traveling on this path moves in a clockwise direction). Take the normal vector to
to be pointing downward, given by

Then the integral is



Both integrals are kind of tedious to compute, but personally I prefer the latter method. Either way, you end up with a value of
.
The pressure due to the depth in a liquid can be calculated as:
P = ρgh; ρ is the density in kg/m³, g is the acceleration due to gravity in m/s² and h is the depth in the fluid.
ρ = 0.65 g/cm³ = 650 kg/m³
P = 650 x 9.81 x 3
= 19100 Pascals
Pressure in atm = 19100/101325 atm
= 0.188 atm
Answer:
d. 3
Step-by-step explanation:
hope this helps!!!!!!!<3
The tenth place is where the 7 is.
0.7
If the number behind it is over 5, we round up. If it isn't, we round down.
0<5
We round down.
2.7 is the answer.
I hope this helps!
~kaikers