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3 years ago

What is the value of n? 9×27+2×31-28=n

Mathematics

2 answers:

gregori [183]3 years ago

4 0

N=277 Hope this helps :)

skelet666 [1.2K]3 years ago

4 0

PEMDAS!! Parentheses exponents multiplication division adding subtracting

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Simplify. (–5q^2p)^3

mr_godi [17]

Answer:

Step-by-step explanation:

$(a*b)^{n} = a^{n}*b^{n}\\\\(a^{n})^{m} = a^{m*n}\\\\ (-5q^{2}*p)^{3}= (-5)^{3}*q^{2*3}*p^{3}\\\\= -125q^{6}p^{3}$

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2 years ago

A line passes through the points (2,13) and (9,20). Write a linear function rule in terms of x and y for this line. The linear f

iren [92.7K]

Answer:

y= (9,13)

Step-by-step explanation:

i think im really sorry if im wrong

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2 years ago

What is 3/4 turn into a percentage?

Hoochie [10]

75% I need to make this longer lol but 75%

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3 years ago

Read 2 more answers

Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

Find the exact solutions of the system

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

Find the values of y

First solution

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

Second solution

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

First solution

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

6 0

3 years ago

PLEASE HELP. Write the equation in slope-intercept form for the line that contains the points

madam [21]

Answer:

y=2x-11

Step-by-step explanation:

3 0

2 years ago