Answer:
∠Q = 53.13 degrees
Step-by-step explanation:
Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle
Hence using the notation
SOH CAH TOA
where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides
Considering ∠Q and the given sides
PR=16cm is the opposite side,
PQ= 12 cm is the adjacent side hence we use TOA
Tan Q = 16/12 =
Q = Arc tan 16/12
= 53.13 degrees
You just have to combine like terms here
6+7n^3 is the final answer
Answer:
C. 92 degrees
Step-by-step explanation:
Given that the 
92° which is one of the angles of the quadrilateral WXYZ
The quadrilateral is first rotated by 270° about the origin and then translated 2 units up, the new position of the quadrilateral is W'X'Y'Z'.
The shape of the quadrilateral is remained unchanged due to rotation and translation, so all the angles of the final quadrilateral W'X'Y'Z' is the same as the angles of the given quadrilateral WXYZ.
So,
By using the given value,
92°
Hence, option (C) is correct.
Answer:
y-4=3(x-2)
Step-by-step explanation:
y-y1=m(x-x1)
Answer:
x = 4 or x = (-3)/2
Step-by-step explanation:
Solve for x over the real numbers:
2 x^2 - 5 x - 12 = 0
x = (5 ± sqrt((-5)^2 - 4×2 (-12)))/(2×2) = (5 ± sqrt(25 + 96))/4 = (5 ± sqrt(121))/4:
x = (5 + sqrt(121))/4 or x = (5 - sqrt(121))/4
sqrt(121) = sqrt(11^2) = 11:
x = (5 + 11)/4 or x = (5 - 11)/4
(5 + 11)/4 = 16/4 = 4:
x = 4 or x = (5 - 11)/4
(5 - 11)/4 = -6/4 = -3/2:
Answer: x = 4 or x = (-3)/2
