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3 years ago

PLEASE HELP

1 answer:

6 0

1. A. y and 1.2y are like terms. c they both contain the same term (y) and can therefore be combined.

2. B. 12x+11 (you have to combine the like terms)

3. 15y+18-4
C. 15y+14 (you must distribute the 3 to inside the parentheses, so 3×5y and 3×6)

4. 9(9-3p) (you have to find a common factor between the terms, in this case 9, and you place it on the outside of the parentheses, while dividing that factor from those terms, which are placed in parentheses.

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Find the volume of the solid whose base is the region Ix I Iy I < 1 and whose vertical cross sections perpendicular to the y-

gavmur [86]

Answer:

volume of the solid = $\frac{\pi }{3}$

Step-by-step explanation:

As given , the region : |x| + |y| $\leq$ 1

when y $\geq$ 0 ,

|x| + y = 1

⇒|x| = 1 - y

when y ≤ 0 ,

|x| - y = 1

⇒|x| = 1 + y

The given region is the rectangle with sides (0, 5) , (0, -5), (5, 0), (-5, 0)

As given , the vertical cross section are semicircle

As we know that the area of semi circle = $\frac{1}{2}$ $\pi x^{2}$

Now,

Volume = $\int\limits^0_-1 {\frac{\pi }{2} (1+y)^{2} } \, dy$ + $\int\limits^1_0 {\frac{\pi }{2} (1-y)^{2} } \, dy$

= $\frac{\pi }{2} (\frac{(1+y)^{3} }{3} )$ - $\frac{\pi }{2} (\frac{(1-y)^{3} }{3} )$

= $\frac{\pi }{6}$ [1-0] - $\frac{\pi }{6}$ [0-1]

= $\frac{\pi }{6} + \frac{\pi }{6} = 2\frac{\pi }{6} = \frac{\pi }{3}$

⇒volume of the solid = $\frac{\pi }{3}$

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21.4666 hope this helps! ❤️

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mario62 [17]

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$f(x,y)=\sin x\sin y+C$

$\displaystyle\int_{\mathcal C}\cos x\sin y\,\mathrm dx+\sin x\cos y\,\mathrm dy=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(\frac{3\pi}2,\frac\pi2\right)-f(0,-\pi)=-1$

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3 years ago

Find the HEIGHT of the rectangular prism given its surface area is 238 square yards.

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Answer:

Height = 5

Step-by-step explanation:

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