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2 years ago

PLEASE HELP

1 answer:

6 0

1. A. y and 1.2y are like terms. c they both contain the same term (y) and can therefore be combined.

2. B. 12x+11 (you have to combine the like terms)

3. 15y+18-4
C. 15y+14 (you must distribute the 3 to inside the parentheses, so 3×5y and 3×6)

4. 9(9-3p) (you have to find a common factor between the terms, in this case 9, and you place it on the outside of the parentheses, while dividing that factor from those terms, which are placed in parentheses.

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720

Step-by-step explanation:

125tablets, 2 of which had broken screens.

multiply 45000 by 2, then divide 125=720

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2 years ago

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2 years ago

You have 19 digs for your current volleyball season. There are 5 games left in the season. You want to break your previous recor

viktelen [127]

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3 years ago

2 more than the difference between 8 and h

mylen [45]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

You are told that a third powered polynomial has zeroes at -1, 2, 5.

vichka [17]

Answer:

a) factors of polynomial are: (x+1)(x-2)(x-5)

b) the required polynomial in standard form is: $\mathbf{x^3-6x^2+3x+10}$

Step-by-step explanation:

The polynomial has zeros at -1,2,5

Part A) Write the three factors of the polynomial

we have x=-1, x=2 and x=5 as zeros of polynomial

so factors will be:

(x+1)=0, (x-2)=0, (x-5)=0

So, factors of polynomial are: (x+1)(x-2)(x-5)

Part B) Write the polynomial in standard form

For finding polynomial, we will multiply all the factors i.e

(x+1)(x-2)(x-5)

$(x+1)(x-2)(x-5)\\=(x(x-2)+1(x-2))(x-5)\\=(x^2-2x+x-2)(x-5)\\=(x^2-x-2)(x-5)\\=x(x^2-x-2)-5(x^2-x-2)\\=x^3-x^2-2x-5x^2+5x+10\\=x^3-x^2-5x^2+5x-2x+10\\=x^3-6x^2+3x+10$

So, the required polynomial in standard form is: $x^3-6x^2+3x+10$

7 0

2 years ago