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3 years ago

Jonas has $75 to spend on new clothes. The pair of jeans he wants costs $48.50. What is the most Jonas can spend on shirts?

Mathematics

1 answer:

Mice21 [21]3 years ago

8 0

Answer:

The most Jonas can spend on shirts is $26.50.

Step-by-step explanation:

Given:

Money Jonas has to spend on new clothes = $75.

The cost of the pair of jeans = $48.50

Now, find the most amount which Jonas can spend on shirts.

So, to get the amount for shirts we subtract the cost of jeans from the total money to spend for new clothes:

⇒ $75-48.50$ $=\$26.50$

So, Jonas remained with $26.50 to spend on shirts.

Therefore, the most Jonas can spend on shirts is $26.50.

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A car rental company charges $10 a day and 17 cents per mile to rent their cars. If the total charge for a 2-day rental were $61

borishaifa [10]

Answer:

245 miles driven.

Step-by-step explanation:

A car rental company charges $10 a day and 17 cents per mile to rent their cars. 17 cents = 0.17 dollars

Let x be the number of miles and y be the number of days

total change =0.17x + 10y

Given total change is 61.65 and number of days = 2

plug in the values and find out the number of miles

61.65 = 0.17 x + 2(10)

61.65 = 0.17 x + 20

subtract 20 on both sides

41.65 = 0.17x

Divide by 0.17 on both sides

x = 245

245 miles driven.

7 0

3 years ago

A total of 41 people attended Rayleigh's birthday party. Rayleigh's sister invited some of the guests. If Raleigh invited 19 mor

Keith_Richards [23]

Her sister invited 22 guests. What you have to do to solve this problem is subtract 41-19. We have to do this because Rayliegh invited 19 more people than her sister, but invited a total of 41 people herself. So, to figure out how many people her sister invited we have to know that Rayliegh invited 19 more people and we have to subtract that from the total number she invited to get how many people her sister invited: 22 guests. Can you make me brainliest?

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3 years ago

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zheka24 [161]

Step-by-step explanation:

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8 0

3 years ago

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Zielflug [23.3K]

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3 0

3 years ago

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

3 years ago