B) 7n−3=n+4
In this case, 'n' is used in place of the word 'number'. 'Product' refers to multiplication, so we multiply n by 7. 3 LESS refers to subtraction, so we subtract 3 from 7n. Then, we know that the solution to that is four more than what the actual number is. MORE refers to addition, so we add 4 to n.
Answer: 8000
Step-by-step explanation:
From the question, we are informed that the expression 10³ × 2^w models the population of the bacteria after w weeks.
The number of bacteria that will be present in 3 weeks will then be:
= 10³ × 2^w
= 10³ × 2³
= 1000 × 8
= 8000 bacterias
a)0.43^5*0.57^5
b)0.43^6*0.57^4
c)0.43^3*0.57^7+0.43^2*0.57^8+0.43^1*0.57^9+0.57^10
Option (c) is correct according to me I think it’s helpful
Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
