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3 years ago

13

Bobbie went snowboarding with friends at 10:10 A.M They snowboarded for 1 hour and 43 minutes, and then stop to eat lunch. What

time did they stop for lunch?

1 answer:

zmey [24]3 years ago

4 0

10:10 + 1:43 = 11:53

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A researcher surveyed people as they left a museum, asking whether they visited the gift shop and whether they watched the film

BARSIC [14]

Hey there!

P(y) = 0.46

P(x) = 0.49

P(y') = 0.54

P(x') = 0.51

P(y and x') = 0

x = person that watched the film

y = person that visited the gift shop

P(y and x') / P(x')

0.1 / 0.51 = 0.196

Now convert that into a percentage!

0.196 = 19.6%

Your answer is 19.6%

Hope I helped!

Let me know if you need anything else!

~ Zoe

5 0

3 years ago

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---<em>Approximated</em>

7 0

4 years ago

Find the equation, in point-slope form, of the line that passes -3 and passes through the point (1,2). plz show your work.

Maslowich

Substitute the given values for the parameters in the point-slope form of the equation of a line. That form is
y - k = m(x - h)
for point (h, k) and slope m.

You have (h, k) = (1, 2) and m=-3, so your equation is
y - 2 = -3(x - 1)

4 0

3 years ago

There are 250 students taking either band or chorus. If there are 180 students taking band and 60 students in both band and chor

storchak [24]

I think it is 60 I'm probably wrong though

8 0

3 years ago

Read 2 more answers

Algebra question: -5x>=15

Kaylis [27]

The answer is in the picture I sent

8 0

3 years ago