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irga5000 [103]
2 years ago
13

The average of five weights is 13 grams. This set of of five weights is then increased by another weight of 7 grams. What is the

average of the 6 weights?
Mathematics
2 answers:
eimsori [14]2 years ago
4 0

Answer:

the answer is 12

Step-by-step explanation:

You just find the total weight and divide it by the number of weights

hope this helped ;3

DiKsa [7]2 years ago
4 0

Answer:

12 g

Step-by-step explanation:

Recall that

Average Weight = Sum of All weights  ÷ Number of Weights

in the first case we are given that average of 5 weights is 13g

i.e Average weight (of 5 weights) = 13g and number of weights = 5

or, using the formula above,

13 = sum of 5 weights ÷ 5   (rearranging)

sum of 5 weights = 13 x 5 = 65 g

we are subsequently told that one more weight of 7 g is added,

hence, new number of weights = 6

and,

sum of 6 weights = sum of original 5 weights + sum of 6th weight

= 65 g + 7 g = 72 g

once again using the first formula

Average Weight (of 6 weights) = Sum of All weights  ÷ Number of Weights

= 72  ÷ 6

= 12g

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= 6/-3 = -2 = m. It's negative because as x increases, y decreases

plug that into the point slope formula, with either point. generally use the most simple point
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simply if you want

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5 0
3 years ago
What is the area around the fence if it’s 6 around and 7 length
patriot [66]

Answer:

42

Step-by-step explanation:

The formula for area is length multiplied by width

7 X 6 = 42

hope this helps :)

7 0
2 years ago
Read 2 more answers
If the radius of a circle is 10cm, what will be the area of the circle?
malfutka [58]

Answer:

314

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve and show work:
Katyanochek1 [597]

Im a keep editing since this is timed.


#1 x-8a/6=3a-2x


Multiply each term by 6 to remove fraction .


6(x-8a/6)= 3a(6)-2x(6)


X-8a=18a-12x


Add 12x both sides


X+12x-8a=18a-12x+12x


13x-8a= 18a


Add8a both sides


13x-8a+8a=18a+8a


13x=26a

Divide each side by 13


13x/13=26a/13


X= 26a/13


Reduce and cancel common factor .


X= 13(2a)/13(1)


X=2a/1


X=2a


Problem #2

3x-2a=7a find a


Subtract 3x both sides


3x-3x-2a=7a-3x


-2a=7a-3x


Subtract 7a both sides

-2a-7a=7a-7a-3x


5a=-3x

Divide both sides by 5

5a/5=-3x/5


A= -0.6 or -3/5


Problem#3

3(bx-2ab)=b(x-7a)+3ab


Distributed property


3(bx)+3(-2ab)=b(x)+b(-7a)+3ab


Simplify

3bx-6ab=bx-7ab+3ab


Add -7a plus 3ab on right side


3bx-6ab= bx-4ab


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2bx=2ab


Divide 2b both sides


X= 2ab/2b


Cancel 2 common


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7 0
2 years ago
Read 2 more answers
Find the slope of the line through p and q. p(1, −9), q(−3, 2)
attashe74 [19]
To find the slope,we can use the point-slope form:
y1 - y2 = m(x1 - x2)
Where m is the slope.

In this case,the equation would be:
-9-2 = m(1-(-3))
-11 = m(1+3)
-11 = 4m
m = -11/4

Therefore the slope is -11/4.

Hope it helps!
7 0
3 years ago
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