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irga5000 [103]
3 years ago
13

The average of five weights is 13 grams. This set of of five weights is then increased by another weight of 7 grams. What is the

average of the 6 weights?
Mathematics
2 answers:
eimsori [14]3 years ago
4 0

Answer:

the answer is 12

Step-by-step explanation:

You just find the total weight and divide it by the number of weights

hope this helped ;3

DiKsa [7]3 years ago
4 0

Answer:

12 g

Step-by-step explanation:

Recall that

Average Weight = Sum of All weights  ÷ Number of Weights

in the first case we are given that average of 5 weights is 13g

i.e Average weight (of 5 weights) = 13g and number of weights = 5

or, using the formula above,

13 = sum of 5 weights ÷ 5   (rearranging)

sum of 5 weights = 13 x 5 = 65 g

we are subsequently told that one more weight of 7 g is added,

hence, new number of weights = 6

and,

sum of 6 weights = sum of original 5 weights + sum of 6th weight

= 65 g + 7 g = 72 g

once again using the first formula

Average Weight (of 6 weights) = Sum of All weights  ÷ Number of Weights

= 72  ÷ 6

= 12g

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Answer:

<h3>Hence required integers are 11 and 13</h3>

Let x an odd positive integer

Then, according to question

x^2 +(x+2)^2=290

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Step-by-step explanation:

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3 years ago
Evaluate f(x) = x2 – 12 when x = 5
Ede4ka [16]

Answer:

f(5) = 13

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Evaluate</u>

  1. Substitute:                   f(5) = 5² - 12
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