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motikmotik
2 years ago
12

If the r-value, or correlation coefficient, of a data set is negative , the coefficient of determination is negative

Mathematics
1 answer:
AleksAgata [21]2 years ago
6 0
This is false because the confection of a determination is native
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A second important result is that electrons will fill the lowest energy states available. This would seem to indicate that every
Assoli18 [71]

Answer:

  • 8

Explanation:

1)<u> Principal quantum number, n = 2</u>

  • n is the principal quantum number and indicates the main energy level.

<u>2) Second quantum number, ℓ</u>

  • The second quantum number, ℓ,  is named, Azimuthal quantum number.

The possible values of ℓ are from 0 to n - 1.

Hence, since n = 2, there are two possible values for ℓ: 0, and 1.

This gives you two shapes for the orbitals: 0 corresponds to "s" orbitals, and 1 corresponds to "p" orbitals.

<u>3) Third quantum number, mℓ</u>

  •    The third quantum number, mℓ, is named magnetic quantum number.

The possible values for mℓ are from - ℓ to + ℓ.

Hence, the poosible values for mℓ when n = 2 are:

  • for ℓ = 0: mℓ = 0
  • for ℓ = 1, mℓ = -1, 0, or +1.

<u>4) Fourth quantum number, ms.</u>

  • This is the spin number and it can be either +1/2  or -1/2.

Therfore the full set of possible states (different quantum number for a given atom) for n = 2 is:

  • (2, 0, 0 +1/2)
  • (2, 0, 0, -1/2)
  • (2, 1, - 1, + 1/2)
  • (2, 1, -1, -1/2)
  • (2, 1, 0, +1/2)
  • (2, 1, 0, -1/2)
  • (2, 1, 1, +1/2)
  • (2, 1, 1, -1/2)

That is a total of <u>8 different possible states</u>, which is the answer for the question.

8 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
3 years ago
Read 2 more answers
Vertical Lines
noname [10]

Answer:

kk

Step-by-step explanation:

8 0
2 years ago
Use polynomial division to completely factor y=x^3+3x^2-13x-15 by x+5
Salsk061 [2.6K]

Answer:

(x - 3)(x + 1)(x + 5)

Step-by-step explanation:

I'd use synthetic division instead.  If we were to find the roots of the given polynomial, we could from them write the factors as well.

The divisor x + 5 corresponds to root x = -5.  Setting up synthetic div.,

-5   )   1    3    -13    -15

               -5     10    +15

      -----------------------------

           1   -2     -3      0

Since the remainder is 0, we know that -5 is a root and (x + 5) is a factor.  Moreover, we know that the coefficients of the quotient are 1, -2 and -3.

1x² - 2x - 3 can be factored:  the factors are (x - 3) and (x + 1).

So the end result for this problem is (x - 3)(x + 1)(x + 5).

7 0
3 years ago
Help ASAP please!!!
masya89 [10]
Total revenue the previous year would be $46,355
7 0
3 years ago
Read 2 more answers
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