Is there one solution, no solution or infinite solutions for 7x+14=7(x+2)
2 answers:
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We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in .
Let's try even though we are forbidden to put 4 inside
we are still able to do so.
So what we just got is the upper limit of the range. The lower limit is
.
So the range is just .
Hope this helps :)