Is (-8, -10) a solution to this system of equations?

Frank purchased a new ice box having 2kg capacity. He wants it to be full with ice cubes. He measured the ice cubes to be 3.5 cm

salantis [7]

Answer:

Frank can put 5 cubes in the box.

Step-by-step explanation:

Formula:

Mass = Volume × density.

1 cubic centimetre = 0.001 liter= 1 millilitre

Given that,

Frank purchase a new ice box having 2 kg capacity.

So,the mass of the cubes is 2 kg.

Each ice cubes measured 3.5 cm by 3.5 cm by 3.5 cm.

The volume of a cube is = $Side ^3$

The volume of a each ice cubes is = $3.5^3$ cm³

= 42.875 ml

The ice cubes have a density of 0.914 g/ml

The mass of each cubes are

=volume of each ice cubes × density

=42.875 ml ×0.914 g/ml

=39.18775 gram.

Let x number of ice cubes he can put in the box.

The mass of x cubes is = 39.18775x grams.

2 kg= 2,000 gram [ since 1 kg= 1000 gram]

According to the problem,

39.18775x=2,000

$\Rightarrow x=\frac{2000}{39.18775}$

$\Rightarrow x\approx 51$

Frank can put 5 cubes in the box.

5 0

3 years ago

find the least perfect square that is exactly divisible by each of the numbers 5 , 18 , 25 and 27 .

Dimas [21]

<h3>☂︎ Answer :- </h3>

8100

<h3>☂︎ Solution :- </h3>

LCM of 5 , 18 , 25 and 27 = 2 × 3³ × 5²
2 and 3 have odd powers . To get a perfect square, we need to make the powers of 2 and 3 even . The powers of 5 is already even .

In other words , the LCM of 5 , 18 , 25 and 27 can be made a perfect square if it is multiplied by 2 × 3 .

The least perfect square greater that the LCM ,

☞︎︎︎ 2 × 3³ × 5² × 2 × 3

☞︎︎︎ 2² × 3⁴ × 5²

☞︎︎︎ 4 × 81 × 85

☞︎︎︎ 100 × 81

☞︎︎︎ 8100

8100 is the least perfect square which is exactly divisible by each of the numbers 5 , 18 , 25 , 27 .

7 0

2 years ago

Suppose we want to choose colors, without replacement, from the colors red, blue, green, and purple.

DerKrebs [107]

The number of ways when the choice is not relevant is 4

<h3>How to determine the number of ways?</h3>

The number of colors are:

Colors, n = 4

The color to choose are:

r = 3

<u>Relevant choice</u>

When the choice is relevant, we have:

$Ways = ^nP_r$

This gives

$Ways = ^4P_3$

Evaluate

Ways = 24

Hence, the number of ways when the choice is relevant is 24

<u>Not relevant choice</u>

When the choice is not relevant, we have:

$Ways = ^nC_r$

This gives

$Ways = ^4C_3$

Evaluate

Ways = 4

Hence, the number of ways when the choice is not relevant is 4

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0

2 years ago

Which steps would you use to solve this equation? Check all that apply.

Dovator [93]

Answer: The answers are

Subtract 7 from both sides of the equation.
Subtract 7 from 7.
Substitute 5 for p to check the solution.

Step-by-step explanation:

p + 7 = 12

= p + 7 - 7 = 12 - 7

= p = 5

Then for the substituting part

5 + 7 = 12

Hope this helps!

3 0

3 years ago

Meg found one treasure at − 3 4 foot. Which of these location are higher than − 3 4 foot? Check all that apply. Negative StartFr

Neporo4naja [7]

Answer:

$\frac{-1}{4}$ and $\frac{-5}{8}$ are the locations higher than $\frac{-3}{4}$ foot

Step-by-step explanation:

We are given that Meg found one treasure at $\frac{-3}{4}$ foot

We are supposed to find Which of these location are higher than $\frac{-3}{4}$ foot?

i) $-\frac{7}{8}$

So, this location is not higher than $\frac{-3}{4}$ foot

ii) $-\frac{1}{4}$

So, $-\frac{1}{4}>\frac{-3}{4}$

So, this location is higher than $\frac{-3}{4}$ foot

iii) - 1 foot

$-1 < \frac{-3}{4}$

So,this location is not higher than $\frac{-3}{4}$ foot

iv)-2 feet

So,this location is not higher than $\frac{-3}{4}$ foot

v) $\frac{-5}{8}$

So, this location is higher than $\frac{-3}{4}$ foot

5 0

3 years ago