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VladimirAG [237]
2 years ago
6

Is (-8, -10) a solution to this system of equations?

Mathematics
1 answer:
Dmitrij [34]2 years ago
8 0

Answer:

No is something worng

Step-by-step explanation:

y= 9/8 * x - 1

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How many 1 inch cubes do you need to create a cube with an edge length of 6 inches?
galben [10]
216 cubes. For the base, you would need 6 x 6 cubes which is 36. Since it is a cube, the height is also 6 so you multiply 36 by 6, which is 216.
6 0
3 years ago
Write the standard equation of a circle that passes through (−2, 10) with center (−2, 6).
Liono4ka [1.6K]
Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
6 0
4 years ago
Read 2 more answers
PLEASE HELP ME 16 POINTS PLEASE HELP
xenn [34]

Answer:

3/1

Step-by-step explanation:

8 0
3 years ago
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Select the two expressions equal to the area of this figure in square centimeters.
zepelin [54]

Answer:

1.(6*4) + (18*6) + (6*4)

1.(6*10) + (6*6) + (6*10)

Step-by-step explanation:

there are two ways to break this shape into three rectangles:

1.Top right rectangle, Top left rectangle, Bottom long rectangle

2. Left rectangle, Middle square, Right rectangle.

5 0
2 years ago
What is the probability of rolling a dice at most 3 times until a 6 occurs
IRISSAK [1]

Answer:

Probablity of getting six in at most three roll= 0.199.

Step-by-step explanation:

Given: Dice rolled at most 3 times untill a 6 occurs.

First, finding the probablity of getting 6 in a dice if rolled once.

Probablity= \frac{chances\ of\ occurance}{Total\ number\ of\ event}

We know, dice have six side, therefore, total number of event will be 6.

∴ Probablity of getting six in one roll= \frac{1}{6}

As given, Dice is rolled at most 3 times.

Now, finding the probablity of getting 6 in a dice if rolled 3 times.

∴ Probablity of getting six in three roll= \frac{1}{6}+(\frac{1}{6})^{2} +(\frac{1}{6})^{3}

⇒ Probablity of getting six in three roll=  \frac{1}{6}+\frac{1}{36} +\frac{1}{216}

Taking LCD 216

⇒Probablity of getting six in three roll= \frac{1\times 36+ 6\times 1+1}{216}

⇒Probablity of getting six in three roll= \frac{43}{216}

∴Probablity of getting six in three roll=0.199

           

3 0
3 years ago
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