hello
we are asked to multiply two mixed fractions.
to do this, we need to convert the mixed fractions to improper fraction
now we can proceed to multiply the two numbers.
simply multiply numerator to numerator and denominator to denominator
the answer to the question is 25/6
Answer:
1) x=6, y=-6 which is (6,-6) as an ordered pair
3) x=10, y=-1 which is (10,-1) as an ordered pair
Step-by-step explanation:
Question 1:
<u>Solve them like an addition problem:</u>
-4x-2y=-12
4x+8y=-24
________
(-4x+4x)+(-2y+8y)=(-12+-24)
0x+6y=-36
6y=-36
y=-6
<u>Plug value of y into one of the original equations:</u>
4x+8(-6)=-24
4x-48=-24
4x=24
x=6
Question 3:
<u>Solve them like an addition problem:</u>
x-y=11
2x+y=19
_______
(x+2x)+(-y+y)=11+19
3x+0y=30
3x=30
x=10
<u>Plug value of x into one of the original equations:</u>
10-y=11
-y=1
y=-1
PEMDAS
7+18/(6-3)
7+18/3
7+6
13
Answer:
$392
Step-by-step explanation:
Given the expression :
Total cost = 20a + 13c
a = adult
c = student
The total cost for 4 adults and 24 students
a = 4 ; c = 24
Total cost :
20(4) + 13(24)
80 + 312
= $392
Nina used 2 cups. The correct answer is B. Use this formula;
lets assume y is the amount of ounces she used. Lets assume x is the amount of cups she used.
y = x(8)
Replace y with 16.
16 = x(8)
Divide by 8.
2 = x
Thus, 2 cups.