Answer:
-6x^6y^5
Step-by-step explanation:
you have to find p such that
(-3
y)(p) = 18
So just divide to find p
p =
= -6
Answer:
The answer is A.
Step-by-step explanation:
Given that Winnona took 5 tests and retake Test 5. So the mean score for this question is Total number of scores divide by Total number of tests is equals to 87 :
Let Test 5's score be x,
Let mean score be 87,

Next you have to solve the value of x :

Answer: he would have $343.47 after 2 years.
Step-by-step explanation:
if he leaves his interest from the first year in the bank, we would assume that his interest was compounded. We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $300
r = 7% = 7/100 = 0.07
n = 1 because it was compounded once in a year.
t = 2 years
Therefore,.
A = 300(1 + 0.07/1)^1 × 2
A = 300(1.07)^2
A = $343.47
Answer:
x = ± 
Step-by-step explanation:
Given
y = x² + 11 ( subtract 11 from both sides )
y - 11 = x² ( take the square root of both sides )
±
=
, hence
x = ± 