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Margarita [4]
3 years ago
7

According to the square root property, the solution set of x 2 = 25 is {±5}. True False

Mathematics
2 answers:
babymother [125]3 years ago
8 0
I believe the correct answer is true. According to the square root property, the solution set of x^2 = 25 is {±5}. <span>The </span>square root property<span> is one method that is used to find the solutions to a quadratic (second degree) equation. This method involves taking the </span>square roots <span>of both sides of the equation. Hope this answers the question.</span>
romanna [79]3 years ago
6 0

True , because ....

5^2 = 25

25 = 25

and also

(-5)^2 = 25

25 = 25

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I need help with this math problem plz help and plz explain your answer​
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34.04 cm²

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Triss [41]

Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
3 years ago
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