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Nataly_w [17]
3 years ago
10

In a class of 27 students, 15 are female and 7 have an A in the class. There are 9

Mathematics
2 answers:
weeeeeb [17]3 years ago
4 0

Answer:

4/15

Step-by-step explanation:

sveticcg [70]3 years ago
3 0

Answer:

4/27

Female:15/27 female with an A:4/15

Male:12/27 male with an A:3/12

Answer=15/27 ×4/15

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Victoria recently switched to a new electric company. If she uses between 0 and 400 kilowatt-hours (kWh) of electricity per mont
Gekata [30.6K]

Answer:

see the explanation

Step-by-step explanation:

<em><u>The question is </u></em>

Identify the domain and the range, using words and inequalities

Let

x -----> the number of kilowatt-hours (kWh) of electricity per month

y ----> the price per month

we know that

Part 1) For the value of x between 0 kWh and 400 kWh

0\ kWh \leq x < 400\ kWh

The price is equal to

y=\$30

therefore

The domain is the interval ------> [0,400)

The domain is all real numbers greater than or equal to 0 kWh  and less than 400 kWh

The range is ($30)

The range is equal to $30

Part 2) For the value of x equal to 400 kWh or more per month

x\geq 400\ kWh

The domain is the interval -----> [400, infinite)

The domain is all real numbers greater than or equal to 400 kWh

The price is

y=0.097x

<em>Find the range</em>

For x=400 kWh

y=0.097(400)=\$38.8

so

y\geq \$38.8

The range is the interval -----> [38.8, infinite)

7 0
3 years ago
In a class, 60% of the students are girls. There are 18 girls in the class.
N76 [4]

Answer:

The answer is 30

Step-by-step explanation:

If you were to do 50% of 30, it would be 15 students that are girls. There's 18 students that are girls though, so the extra 10% would make 18 students in the class girls. The remaining 40% would be 12 boys. So basically you're taking 10% from one side and putting it in the other because 50% of 30 is 15 (well this is at least how I would do it, I don't know how others would do it though)

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
3 years ago
Can y’all help me on question 6?!
myrzilka [38]
The correct answer would be A. Hope this helps
6 0
3 years ago
Last year Billy weighed 75kg. This year he weighed 90kg. With what percentage did his weight increase. SHOW ALL WORK!!!
k0ka [10]

Answer:

20%

Step-by-step explanation:

90 - 75 = 15

15 ÷ 75 = 0.2

0.2 x 100% = 20%

8 0
3 years ago
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