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Nataly_w [17]
2 years ago
10

In a class of 27 students, 15 are female and 7 have an A in the class. There are 9

Mathematics
2 answers:
weeeeeb [17]2 years ago
4 0

Answer:

4/15

Step-by-step explanation:

sveticcg [70]2 years ago
3 0

Answer:

4/27

Female:15/27 female with an A:4/15

Male:12/27 male with an A:3/12

Answer=15/27 ×4/15

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The cost of an online video streaming service is $9.99 per
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15. Find the length of x. Round to 1 decimal place.
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15/x = 5/11

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2 years ago
Solve the equation for v<br> <img src="https://tex.z-dn.net/?f=y%3D%5Cfrac%7B8%7D%7Bav%7D%20%2B7" id="TexFormula1" title="y=\fra
My name is Ann [436]

Answer:

v = \dfrac{8}{a(y - 7)}

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y = \dfrac{8}{av} + 7

Subtract 7 from both sides.

y - 7 = \dfrac{8}{av}

Multiply both sides by v.

v(y - 7) = \dfrac{8}{a}

Multiply both sides by 1/(y - 7).

v = \dfrac{8}{a(y - 7)}

3 0
3 years ago
An independent-measures research study was used to compare two treatment conditions with n= 12 participants in each treatment. T
Maurinko [17]

Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

Step-by-step explanation:

Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

Test statistic (t) = (M1 - M2) ÷ sqrt [pooled variance (1/n1 + 1/n2)] = (55 - 52) ÷ sqrt[6(1/6 + 1/6)] = 3 ÷ 1.414 = 2.122

Degree of freedom = n1+n2-2 = 12+12-2 = 22

(a) For a two-tailed test with a 0.05 (5%) significance level and 23 degrees of freedom, the critical values are -2.069 and 2.069.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

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3 years ago
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