What is 70 times five

Identify the factors of 6ab − 8a + 21b − 28. (5 points)

cupoosta [38]

Rearrange to

6ab+21b-8a-28 now factor 1st and 2nd pair of terms...

3b(2a+7)-4(2a+7)

(3b-4)(2a+7)

So it is the third one down...

4 0

2 years ago

Read 2 more answers

Natalie has $5000 and decides to put her money in the bank in an account that has a 10% interest rate that is compounded continu

kakasveta [241]

Step-by-step explanation:

Natalie has $5000

She decides to put her money in the bank in an account that has a 10% interest rate that is compounded continuously.

Part a) What type of exponential model is Natalie’s situation?

Answer:

As Natalie's situation implies

continuous compounding. So, instead of computing interest on a finite number of time periods, for instance monthly or yearly, continuous compounding computes interest assuming constant compounding over an infinite number of periods.

So, it requires the more generalized version of the principal calculation formula such as:

$P\left(t\right)=P_0\times \left[1+\left(i\:/\:n\right)\right]^{\left(n\:\times \:\:t\right)}$

or

$P\left(t\right)=P_0\times \left[1+\left(\frac{i}{n}\:\right)\right]^{\left(n\:\times \:\:t\right)}$

Here,

$i$ = interest rate

= number of compounding periods

$t$ = time period in years

Part b) Write the model equation for Natalie’s situation?

For continuous compounding the number of compounding periods, $n$ , becomes infinitely large.

Therefore, the formula as we discussed above would become:

$P\left(t\right)=P_0\times e^{\left(i\:\times \:t\right)}$

Part c) How much money will Natalie have after 2 years?

Using the formula

$P\left(t\right)=P_0\times e^{\left(i\:\times \:t\right)}$

$₂ $=\:6107.02$ $

So, Natalie will have $\:6107.02$ $ after 2 years.

Part d) How much money will Natalie have after 2 years?

Using the formula

$P\left(t\right)=P_0\times e^{\left(i\:\times \:t\right)}$

$₁₀ $=13.597.50$ $

So, Natalie will have $13.597.50$ $ after 10 years.

Keywords: word problem, interest

Learn more about compound interest from brainly.com/question/6869962

#learnwithBrainly

5 0

2 years ago

Which of the following inequalities is graphed below?

nikklg [1K]

A : y is greater than or equal to 4x plus two

6 0

3 years ago

Plz help me solve this page ASAP 20POINTS!!!!!

eduard

1) Midpoint : (7/2,1/2), Quadrant 1

2. Midpoint: (5,1/2), Quadrant 2

Hope this helps. Please mark brainliest if you can

8 0

3 years ago

(1 point) In this problem we show that the function f(x,y)=7x−yx+y f(x,y)=7x−yx+y does not have a limit as (x,y)→(0,0)(x,y)→(0,0

polet [3.4K]

Answer:

Step-by-step explanation:

Given that,

f(x, y)=7x−yx+y

We want to show that the limit doesn't exist as (x, y)→(0,0).

Limits typically fail to exist for one of four reasons:

1. The one-sided limits are not equal

2. The function doesn't approach a finite value

3. The function doesn't approach a particular value

4. The x - value is approaching the endpoint of a closed interval

a. Considering the case that y=3x

lim(x,y)→(0,0) 7x−yx+y

Since y=3x

lim(x,3x)→(0,0) 7x−3x(x)+3x

lim(x,3x)→(0,0) 10x−3x²

Therefore,

lim(x,3x)→(0,0) 10x−3x² = 0-0=0

b. Let also consider at y=4x

lim(x,y)→(0,0) 7x−yx+y

Since y=4x

lim(x,4x)→(0,0) 7x−4x(x)+4x

lim(x,4x)→(0,0) 11x−4x²

Therefore,

lim(x,4x)→(0,0) 11x−4x² = 0-0=0

c. Let also consider it generally at y=mx

lim(x,y)→(0,0) 7x−yx+y

Since y=mx

lim(x,mx)→(0,0) 7x−mx(x)+mx

lim(x, mx)→(0,0) (7+m)x−mx²

Therefore,

lim(x, mx)→(0,0) (7+m)x−mx² = 0-0=0

But the limit of the given function exist.

So let me assume the function is wrong and the question meant.

f(x, y)= (7x−y) / (x+y)

So, let analyze again

a. Considering the case that y=3x

lim(x,y)→(0,0) (7x−y)/(x+y)

Since y=3x

lim(x,3x)→(0,0) (7x−3x)/(x+3x)

lim(x,3x)→(0,0) 4x/4x

lim(x,3x)→(0,0) 1

Therefore,

lim(x,3x)→(0,0) 1= 1

So the limit is 1

b. Let also consider at y=4x

lim(x,y)→(0,0) (7x−y)/(x+y)

Since y=4x

lim(x,4x)→(0,0) (7x−4x)/(x+4x)

lim(x,4x)→(0,0) 3x/5x

lim(x,4x)→(0,0) 3/5

Therefore,

lim(x,4x)→(0,0) 3/5 = 3/5

So the limit is 3/5

This show that the limit does not exit.

Since one of the condition given above is met, then the limit does not exist. i.e. The function doesn't approach a particular value

c. Let also consider it generally at y=mx

lim(x,y)→(0,0) (7x−y)/(x+y)

Since y=mx

lim(x,mx)→(0,0) (7x−mx)/(x+mx)

lim(x,mx)→(0,0) (7-m)x/(1+m)x

lim(x, mx)→(0,0) (7-m)/(1+m)

Therefore,

lim(x, mx)→(0,0) (7-m)/(1+m) = (7m)/(1+m)

Then, the limit is (7-m)/(1+m)

So the limit doesn't not have a specific value, it depends on the value of m, so the limit doesn't exist.

7 0

3 years ago