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2 years ago

64=(x+8)+90what does x equal

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

$Solution, solve\:for\:x,\:64=\left(x+8\right)+90\quad :\quad x=-34$

$Steps:$

$64=\left(x+8\right)+90$

$\mathrm{Switch\:sides}, \left(x+8\right)+90=64$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a, x+8+90=64$

$\mathrm{Add\:the\:numbers:}\:8+90=98, x+98=64$

$\mathrm{Subtract\:}98\mathrm{\:from\:both\:sides}, x+98-98=64-98$

$\mathrm{Simplify}, x=-34$

$\mathrm{The\:Correct\:Answer\:is\:x=-34}$

$\mathrm{Hope\:This\:Helps!!!}$

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PLZ HLP! You ask 125 randomly chosen students to name their favorite food. There are 1500 students in the school. Predict the nu

arsen [322]

Answer:

696

Step-by-step explanation:

58/125 = 46.4%

0.464 x 1500 = 696 people

6 0

2 years ago

exis [7]

Answer:

Part 1) The length of the longest side of ∆ABC is 4 units

Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

Step-by-step explanation:

Part 1) Find the length of the longest side of ∆ABC

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

The ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

x ----> the length of the longest side of ∆ABC

y ----> the length of the longest side of ∆DEF

$z=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$y=40\ units$

substitute

$\frac{1}{10}=\frac{x}{40}$

solve for x

$x=(40)\frac{1}{10}$

$x=4\ units$

therefore

The length of the longest side of ∆ABC is 4 units

Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of ∆ABC

y ----> the area of ∆DEF

$z^{2}=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$z^2=(\frac{1}{10})^2$

$z^2=\frac{1}{100}$

therefore

The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

3 0

2 years ago

A stadium has 50,000 seats. Seats sell for $25 in section A, $20 in section B, and $15 in section C. The number of seats in sect

Novay_Z [31]

Answers:

section A = 25,000 seats

section B = 14,200 seats

section C = 10,800 seats

Your teacher may want you to leave out the commas from each number.

=============================================================

Work Shown:

A = number of seats in section A
B = number of seats in section B
C = number of seats in section C

A = B+C

A+B+C = 50,000

B+C+B+C = 50,000

2(B+C) = 50,000

B+C = 50,000/2

B+C = 25,000

C = 25,000 - B

25A + 20B + 15C = 1,071,000

25(B+C) + 20B + 15C = 1,071,000

25(25,000) + 20B + 15(25,000 - B) = 1,071,000

625,000 + 20B + 375,000 - 15B = 1,071,000

1,000,000 + 5B = 1,071,000

5B = 1,071,000 - 1,000,000

5B = 71,000

B = (71,000)/5

B = 14,200 is the number of seats in section B

C = 25,000 - B

C = 25,000 - 14,200

C = 10,800 is the number of seats in section C

A = B+C

A = 14,200 + 10,800

A = 25,000 is the number of seats in section A

--------------

Check:

A+B+C = 25,000+14,200+10,800 = 50,000

5 0

1 year ago

-3x^2 plus 24x = 27 <br> complete the square

Rudik [331]

You can divide the whole expression by -3:

$-3x^2+24x=27 \iff x^2-8x = -9$

Recalling that

$(x-a)^2=x^2-2ax+a^2$

Let's compare the middle term:

$-8x = -2ax \iff a=4$

So, we want to complete

$(x-4)^2 = x^2-8x+16$

Which differs from $x^2-8x$ by 16. So, if we add 16 to both sides, we have

$x^2-8x=-9 \iff x^2-8x+16=7 \iff (x-4)^2=7$

3 0

3 years ago

Read 2 more answers

A right triangle has a side with length 12 in and a hypotenuse with length 20 in. find the length of the missing leg. (round to

OLEGan [10]

Let the unknown side be "z" inches
Through pythagoras:
${12}^{2} + {z}^{2} = {20}^{2}$
Because the square of the two sides add up to the square of the hypotenuse in a right triangle.

This means that
${z }^{2} = {20}^{2} - {12}^{2}$
${z}^{2} = 400 - 144 = 256$
$z = \sqrt{256} = 16$
So the missing side is 16 inches

Hope this helped

6 0

2 years ago