64=(x+8)+90what does x equal

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

$Solution, solve\:for\:x,\:64=\left(x+8\right)+90\quad :\quad x=-34$

$Steps:$

$64=\left(x+8\right)+90$

$\mathrm{Switch\:sides}, \left(x+8\right)+90=64$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a, x+8+90=64$

$\mathrm{Add\:the\:numbers:}\:8+90=98, x+98=64$

$\mathrm{Subtract\:}98\mathrm{\:from\:both\:sides}, x+98-98=64-98$

$\mathrm{Simplify}, x=-34$

$\mathrm{The\:Correct\:Answer\:is\:x=-34}$

$\mathrm{Hope\:This\:Helps!!!}$

You might be interested in

when you subtract one negative integer from another will your answer be greater than or less than integer you started with? Expl

pshichka [43]

Lets take (-4) - (-6)
= -4 + 6 (here we changed the sign because in integers when you are subtracting <span>an integer, we put its opposite..thats the rule .)
=. -4 + 6 = 2

so here we got the answer as 2 .....this shows that </span>your answer will be less than the integer you started with ....this is because here in subtraction we will first change the sign and then follow the same rules of addition ...so here if both the numbers have opposite signs then we subtract and put the greater number sign .....
<span>
Hope i am right !!!</span>

6 0

2 years ago

The length of a rectangle is 4 less than twice the width. If the perimeter of the rectangle is 130, find the length of the recta

Alchen [17]

Answer:

Let L be the length of the rectangle and w be the width of the rectangle.

"The lenght of a rectangle is one less than twice the width" means L=2W-1

Using perimeter formula of a rectangle which is P=2(L+W) you have:

P=2(L+W)

130=2(2W-1+W)

Solve equation above to find W

130=2(3W-1)