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alexandr1967 [171]
3 years ago
6

Un submarino puede descender a una velocidad de –2,5 metros / segundo. Supongamos que el submarino comienza a una profundidad de

–25 metros. ¿Cuánto tiempo le tomaría al submarino alcanzar su profundidad máxima de –200 metros?
Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

17.5

Step-by-step explanation:

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Find two numbers whos diffrence is 16 and the product is 720
antiseptic1488 [7]

Answer:

the numbers who's difference is 16 and the product is 720 is

36 &20

Explanation:

to finding numbers you have to express the equation in a quadratic equation then Factor it.

since the two numbers have a difference of 16 you can say that the first number is x and the second number is x -16 then their product is 720.

x(x-16)=720

x²-16x=720

x²-16x-720=0

(x-36)(x+20)

there are two possible value of x but since you are looking for the positive value of x, choose the positive value of x the first number is 20.

To find the second number

x-16=20

x=20+16

x=36

the second number is 36

<u>Now </u><u>to </u><u>check</u>

<u>3</u><u>6</u><u>-</u><u>2</u><u>0</u><u>=</u><u>1</u><u>6</u>

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8 0
3 years ago
Simplify the expression.<br> - (m<br> m + 3n - 13)
natulia [17]

Answer:

=  -  {m}^{2}  - 3n + 13

Step-by-step explanation:

- (m \times m + 3n - 13)

m \times m =  {m}^{1}  \times m

{m}^{1}  \times  {m}^{1}  =  {m}^{1 + 1} =  {m}^{2}

- ( {m}^{2}  + 3n - 13)

=  -  {m}^{2}  - 3n + 13

7 0
3 years ago
hat is the difference between the areas of a circular table with diameter 6 ft and a circular table with diameter 8 ft?
prohojiy [21]
I believe it’s pie times radius squared so 6ft = 3.14•3 squares and 8ft = 3.14•4 squares and then subtract
7 0
3 years ago
1/10 of ______ is 10 times as much as 8
koban [17]
The answer is 800.
To find this, multiply 10 times 8 to find the number you are dividing. (80) now, multiply 80 by 10. (800)
1/10 of 800 is 80, which is ten times as much as 8.
3 0
3 years ago
What is the slope and y-intercept of the equation on the graph?
Fynjy0 [20]
The answer is B :)
hope this helps you out 
3 0
3 years ago
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