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alexandr1967 [171]
3 years ago
6

Un submarino puede descender a una velocidad de –2,5 metros / segundo. Supongamos que el submarino comienza a una profundidad de

–25 metros. ¿Cuánto tiempo le tomaría al submarino alcanzar su profundidad máxima de –200 metros?
Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

17.5

Step-by-step explanation:

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KatRina [158]

Answer:

12.8

Step-by-step explanation:

Here multiplication is done before addition.

Given

4.8 × 2 + 3.2 ← perform multiplication

= 9.6 + 3.2 ← perform addition

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find the equation of the line passing through the given point and perpendicular to the given equation write your answer in slope
Paraphin [41]

Slope-intercept form:

y = mx + b      "m" is the slope, "b" is the y-intercept


For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2



3.) y = 2x - 2

The given line's slope is 2, so the perpendicular line's slope is -1/2

y=-\frac{1}{2}x+b To find "b", plug in the point (-5 , 5) into the equation

5=-\frac{1}{2}(-5)+b

5=\frac{5}{2}+b     Subtract 5/2 on both sides

5-\frac{5}{2}=b   Make the denominators the same

\frac{10}{2}-\frac{5}{2}=b

\frac{5}{2}=b


y=-\frac{1}{2}x+\frac{5}{2}



4.) -6x + 5y = -10     Get "y" by itself, add 6x on both sides

5y = -10 + 6x          Divide 5 on both sides

y=-2+\frac{6}{5}x

The given line's slope is 6/5, so the perpendicular line's slope is -5/6.

y=-\frac{5}{6}x+b       Plug in (-2, 5)

5 = -\frac{5}{6}(-2)+b

5=\frac{10}{6}+b\\ 5=\frac{5}{3}+b    Subtract 5/3 on both sides

5-\frac{5}{3} =b    Make the denominators the same

\frac{15}{3}-\frac{5}{3}=b\\\frac{10}{3} =b


y = -\frac{5}{6}x+\frac{10}{3}



7.) Perpendicular line's slope is -2

y = -2x + b      Plug in (1,4)

4 = -2(1) + b

4 = -2 + b

6 = b


y = -2x + 6



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Which of the following is an extraneous solution of startroot 4 x 41 endroot = x 5? x = –8 x = –2 x = 2 x = 8
Gnom [1K]

The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.

<h3>What is an extraneous solution?</h3>

It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.

✓4x + 41 = x + 5

Square both sides

4x + 41 = x² + 10x + 25

x² + 6x - 16

x(x + 8) - 2(x + 8) = 0

x + 8 = 0

x= 0 + 8 = 8

Learn more about extraneous solution on:

brainly.com/question/295656

#SPJ4

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Serjik [45]

Answer:

Angles 7 and 8 are supplementary because they are a pair of adjacent angles that form a straight line.

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