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Elena-2011 [213]
3 years ago
6

Write an algebraic expression for the verbal expression the sum of g squared and four.

Mathematics
1 answer:
frez [133]3 years ago
3 0

Answer:

g^2 + 4

I literally do not know how to explain it. I solved this problem with the clues like sum and squared. I looked at where these words were located.

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Find the length of an arc of 40° in a circle with an 8 inch radius.
gulaghasi [49]

Answer:

5.59 inch

Step-by-step explanation:

Arc Length = 2 * π * 8 * (40/360) = 16π/9 = 5.59

6 0
4 years ago
“Write five sentences about proportional relationships”
ivolga24 [154]

Answer:

Now, we’re going to consider an example of proportional relationship in our everyday life: When we put gas in our car, there is a relationship between the number of gallons of fuel that we put in the tank and the amount of money we will have to pay. In other words, the more gas we put in, the more money we’ll pay.

Step-by-step explanation:

hope this helps

7 0
3 years ago
Read 2 more answers
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
Homework due tomorrow pls help !!
Andrej [43]
8+3+11=22
8 divided by 2=4
11-3=8
2+3+3=8
soo =8
♦️=3
⭐️=11
5 0
2 years ago
Read 2 more answers
Which statements about mass are true?
viva [34]

Answer:

1=false 2=false 3=true 4=true 5=false 6=false

Step-by-step explanation:

5 0
2 years ago
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