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2 years ago

Multiplying and factoring polynomial expressions (9th grade)

Mathematics

1 answer:

lutik1710 [3]2 years ago

5 0

Answer:

1. 2(a^2 + 3a + 9)

2. 5(x^2 - 1)

3. 3(t + 8)(t - 2)

4. n(4 - n)

Step-by-step explanation:

For 1, you can only factor out the constant from each.

For 2, you can also only factor out the constant, but remember that you include the 1 when dividing 5 by 5.

For 3, you can factor out the constant and the variables.

For 4, you can only factor out the variable.

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Why are new offers APRs higher than existing account APRs?

Kamila [148]

Answer:

The APR reflects the interest rate plus the fees you paid directly to the lender or broker or both: origination charges, discount points and any other costs. Those fees add to the cost of the loan, and APR takes them into account. That's why APR is higher than the interest rate.

Step-by-step explanation:

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6 0

3 years ago

What is the period of the graph of y=1/2 sin (2x)-3? A.3 B.2 C.1/2 D. Pi

docker41 [41]

The period of the y=1/2 sin (2x)-3 is 2.

We have given that,

y=1/2 sin (2x)-3

We have to determine the period

<h3>What is the period?</h3>

A period is the part of the menstrual cycle when a woman bleeds from her vagina for a few days.

Normally the period of sin(2x) is 2x, but the pi inside the sin(2x) is a horizontal compression by a factor of 1/pi.

So 2pi·1/pi = 2

The 1/2 and -3 do not impact the period. Those just impact the amplitude (vertical aspect) of the graph.

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brainly.com/question/879750

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2 years ago

A) 12, 10, 7,3, Rule: b) 1,3,9, 27, Rule: I c) 4, 19, 34, 49 Rule:

sergejj [24]

A the rule would be -1 times X
B the rule would be x3
C the rule would be +15

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3 years ago

The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the

ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/ $\sqrt{n}$ )

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/ $\sqrt{n}$

The upper limit => C.I_u = μ + Z*σ/ $\sqrt{n}$

The lower limit => C.I_l = μ - Z*σ/ $\sqrt{n}$

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/ $\sqrt{n}$ )

= 200 + (1.96*30)/ $\sqrt{n}$

= 200 + 58.8/ $\sqrt{n}$

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3 years ago

Two of the golf scores at the local tournament were unreadable, but the mean score was 85 and the lowest score was 75. if the re

Vika [28.1K]

Step-by-step explanation:

Assuming the readable scores are:

100, 82, 95, __ , 90, 81, 75, 83, __

We know the mean (or average) is 85, so:

85 = (100 + 82 + 95 + x + 90 + 81 + 75 + 83 + y) / 9

765 = 606 + x + y

159 = x + y

We know the lowest score is 75, so x and y must be at least 76. Possible answers are:

76 and 83

77 and 82

78 and 81

79 and 80

80 and 79

81 and 78

82 and 77

83 and 76

6 0

3 years ago