Answer:
C
Step-by-step explanation:
C
Step-by-step explanation:
you can relate both the unit in one form
Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
Answer:
Step-by-step explanation:
1/3 (3x+12)
1/3×3x+1/3×12
x+4
Answer:
55 ft.
Step-by-step explanation:
First find the area of Lot X
67 • 70 = 4,690
Subtract the are of Lot X from the total area
8,375 - 4,690 = 3,685
3,685 is the area of Lot Y
Now divide 3,685 by the length of Lot Y : 67
3,685 ÷ 67 = 55
The width of Lot Y is 55 ft.
Hope this helps!
