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Fittoniya [83]
3 years ago
13

drew has 32 toy cars. He trades 7 of those cars for 11 others toy cars. how many toy cars does drew have now.

Mathematics
2 answers:
Jet001 [13]3 years ago
8 0
Drew has 36 cars now.
Karolina [17]3 years ago
6 0
Drew now has 36 toy cars
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Mary has four daughters, and each of her daughters has a brother. How many children does Mary have?
Jet001 [13]

Answer:

um 8??

Step-by-step explanation:

5 0
3 years ago
EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If
amm1812

Answer:

To Prove: 9e^x is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If f(x) = 9e^x, then f ^{(n + 1)(x)} =9e^x for all n. If d is any positive number and   |x| ≤ d, then |f^{(n + 1)(x)}| = 9e^x\leq  9e^d.

So Taylor's Inequality, with a = 0 and M = 9e^d, says that |R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq  d.

Notice that the same constant M = 9e^d works for every value of n.

But, since lim_{n\to\infty}\dfrac{x^n}{n!} =0 $ for every real number x$,

We have lim_{n\to\infty} \dfrac{9e^d}{(n+1)!} |x|^{n + 1} =9e^d lim_{n\to\infty} \dfrac{|x|^{n + 1}}{(n+1)!} =0

It follows from the Squeeze Theorem that lim_{n\to\infty} |R_n(x)|=0 and therefore lim_{n\to\infty} R_n(x)=0 for all values of x.

THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and  $ lim_{n\to\infty} R_n(x)=0 \:  for \: |x-a|

By this theorem above, 9e^x is equal to the sum of its Maclaurin series, that is,

9e^x=\sum_{n=0}^{\infty}\frac{9x^n}{n!}  for all x.

6 0
3 years ago
Value of this pronumeral
STatiana [176]
90+80+90+x=360
260+x=360
x=100
4 0
4 years ago
A certain insecticide kills 80% 80% of all insects in laboratory experiments. A sample of 14 insects is exposed to the insectici
Anna [14]

Answer: The probability that exactly 2 insects will survive = 0.2501

Step-by-step explanation:

Given: A certain insecticide kills 80% of all insects in laboratory experiments.

The probability that a particular insect survives= 1-0.80=0.20

Sample size: n=14

Binomial probability distribution:

P(X=x)=\ ^nC_xp^x(1-p)^{n-x}, where x= number of successes , p=probability of success in each trial, n= sample size.

The probability that exactly 2 insects will survive = ^{14}C_2(0.20)^2(0.80)^{12}

\\\\=\dfrac{14!}{2!12!}(0.04)(0.068719476736)\\\\=0.2501

Hence, the probability that exactly 2 insects will survive = 0.2501

6 0
3 years ago
Use compass and straightedge moves to construct the angle bisector for angle ABC. In other words, create a ray that divides angl
denpristay [2]

Lets look at the steps to construct

  • First put compass on point A .
  • Take more distance than half of AC.
  • Then tick a little semicircle.
  • Plot the compass on C.
  • Now join the intersection point with B.

We are done

7 0
3 years ago
Read 2 more answers
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