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3 years ago

drew has 32 toy cars. He trades 7 of those cars for 11 others toy cars. how many toy cars does drew have now.

Mathematics

2 answers:

Jet001 [13]3 years ago

8 0

Drew has 36 cars now.

Karolina [17]3 years ago

6 0

Drew now has 36 toy cars

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Mary has four daughters, and each of her daughters has a brother. How many children does Mary have?

Jet001 [13]

Answer:

um 8??

Step-by-step explanation:

5 0

3 years ago

EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If

amm1812

Answer:

To Prove: $9e^x$ is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If $f(x) = 9e^x$ , then $f ^{(n + 1)(x)} =9e^x$ for all n. If d is any positive number and |x| ≤ d, then $|f^{(n + 1)(x)}| = 9e^x\leq 9e^d.$

So Taylor's Inequality, with a = 0 and M = $9e^d$ , says that $|R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq d.$

Notice that the same constant $M = 9e^d$ works for every value of n.

But, since $lim_{n\to\infty}\dfrac{x^n}{n!} =0 $ for every real number x$$ ,

We have $lim_{n\to\infty} \dfrac{9e^d}{(n+1)!} |x|^{n + 1} =9e^d lim_{n\to\infty} \dfrac{|x|^{n + 1}}{(n+1)!} =0$

It follows from the Squeeze Theorem that $lim_{n\to\infty} |R_n(x)|=0$ and therefore $lim_{n\to\infty} R_n(x)=0$ for all values of x.

$THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and $ lim_{n\to\infty} R_n(x)=0 \: for \: |x-a|$

By this theorem above, $9e^x$ is equal to the sum of its Maclaurin series, that is,

$9e^x=\sum_{n=0}^{\infty}\frac{9x^n}{n!}$ for all x.

6 0

3 years ago

Value of this pronumeral

STatiana [176]

90+80+90+x=360
260+x=360
x=100

4 0

4 years ago

A certain insecticide kills 80% 80% of all insects in laboratory experiments. A sample of 14 insects is exposed to the insectici

Anna [14]

Answer: The probability that exactly 2 insects will survive = 0.2501

Step-by-step explanation:

Given: A certain insecticide kills 80% of all insects in laboratory experiments.

The probability that a particular insect survives= 1-0.80=0.20

Sample size: n=14

Binomial probability distribution:

$P(X=x)=\ ^nC_xp^x(1-p)^{n-x}$ , where x= number of successes , p=probability of success in each trial, n= sample size.

The probability that exactly 2 insects will survive = $^{14}C_2(0.20)^2(0.80)^{12}$

$\\\\=\dfrac{14!}{2!12!}(0.04)(0.068719476736)\\\\=0.2501$

Hence, the probability that exactly 2 insects will survive = 0.2501

6 0

3 years ago

Use compass and straightedge moves to construct the angle bisector for angle ABC. In other words, create a ray that divides angl

denpristay [2]

Lets look at the steps to construct

First put compass on point A .
Take more distance than half of AC.
Then tick a little semicircle.
Plot the compass on C.
Now join the intersection point with B.

We are done

7 0

3 years ago

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