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Cloud [144]
3 years ago
13

Angelo brought apples and bananas at the fruit stand. He bought 20 pieces of fruit and spent $11.50 apples cost $.50 and bananas

cost $.75 each
Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Angelo bought 14 apples and 6 bananas

<em><u>Solution:</u></em>

Let "a" be the number of apples bought

Let "b" be the number of bananas bought

Cost of 1 apple = $ 0.50

Cost of 1 banana = $ 0.75

<em><u>He bought 20 pieces of fruit. Therefore,</u></em>

number of apples bought + number of bananas bought = 20

a + b = 20 -------- eqn 1

<em><u>He spent $ 11.50. Therefore, we frame a equation as:</u></em>

number of apples x Cost of 1 apple + number of bananas x Cost of 1 banana = 11.50

a \times 0.50 + b \times 0.75 = 11.50

0.50a + 0.75b = 11.50 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

a = 20 - b ------ eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.50(20 - b) + 0.75b = 11.50

10 - 0.5b + 0.75b = 11.50

0.25b = 11.50 - 10

0.25b = 1.5

Divide both sides of equation by 0.25

<h3>b = 6</h3>

<em><u>Substitute b = 6 in eqn 3</u></em>

a = 20 - 6

<h3>a = 14</h3>

Thus he bought 14 apples and 6 bananas

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