3.25+0.5x+1 1/3 + 5/6 x=5 11/12 what is x? PLZ HELP DUE SOON
2 answers:
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The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)
<h3>What is a function?</h3>It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)
Let
f(x) = ax² + bx + c
Plug x = 0, and y = 2
c = 2 ...(1)
Plug x = 1 and y = 0
a + b + c = 0 ..(2)
Plug x = -1 and y = 0
a - b + c = 0 ...(3)
After solving (1), (2), and (3)
a = -2
b = 0
c = 2
f(x) = -2x² + 2
Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)
Learn more about the function here:
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<h3>Answer: point Q is located at (-1, 1)</h3>
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Explanation:
Check out the diagram below.
Plot R(-3,7) and T(3,-11) on the same xy grid.
Draw a vertical line through R and a horizontal line through T. A right triangle forms. At the intersection point is point S(-3,-11)
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Now measure the distance from point S to point T. You can count out the spaces or subtract the x coordinates and use absolute value.
|x1-x2| = |-3-3| = |-6| = 6
From point S to point T is 6 units.
We want to subdivide this horizontal length in the ratio 1:2
What this means is that we want to plot a point U somewhere such that SU:UT = 1:2
In other words,
SU = x
UT = 2x
SU+UT = ST
x+2x = 6
3x = 6
x = 6/3
x = 2
So we must move 2 spaces to the right from point S to get to U(-1,-11)
Going from point U(-1,-11) to T(3,-11) is 4 spaces
We have SU:UT = 2:4 = 1:2 to help confirm we have the correct location for point U
From point U, we then move straight up to the line segment RT
We'll land on Q(-1,1)
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Another way to find the y coordinate of point Q is to subdivide the segment RS into the ratio 1:2 similar to how we divided ST up
Segment RS is 18 units long since we go from y = 7 to y = -11 when going from R to S.
If V was on segment RS such that
RV:VS = 1:2
and RV = y
then
RV+VS = RS
y+2y = 18
3y = 18
y = 6
RV = y = 6
VS = 2y = 2*6 = 12
So you'll move 6 units down from y = 7 to land on y = 1 (when going from the y coordinate of R to the y coordinate of Q)