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Stells [14]
3 years ago
14

Which of these numbers are divisible by two a) 243 b) 634 c) 937 d) 58 930

Mathematics
2 answers:
lidiya [134]3 years ago
7 0
I would say b sorry if i'm wrong tho
Ipatiy [6.2K]3 years ago
4 0
The answers are both B and D
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5x+3y=17 solve for y
Alecsey [184]
5x+3y=17
3y=-5x+17
y=-5/3y + 17/3

Graph if it asks.
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3 years ago
jasmine wants to build a 2 5/6 meter long garden path paved with square stones that measure 1/4 meter on each side there will be
patriot [66]
2 \frac{5}{6}*2= \frac{17}{6}* \frac{2}{1} = \frac{17}{3}= 5\frac{2}{3}

5 \frac{2}{3}: \frac{1}{4}=   \frac{17}{3}* \frac{4}{1}=  \frac{68}{3} =22 \frac{2}{3}

23 stones will be needed 
(you have to round up, since you can't have a fraction of a stone)
4 0
3 years ago
Read 2 more answers
A restaurant uses 150 grams of ham on each sub sandwich that it sells. If the restaurant sells 50 sub sandwiches, how much ham w
Morgarella [4.7K]

If the restaurant uses 150 grams and then sells 50 sub sandwiches

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8 0
1 year ago
How do I solve 300x300=
UNO [17]

Answer:

its 90,000

Step-by-step explanation:

just put the zeros together then multiply 3x3

5 0
3 years ago
Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years sinc
nekit [7.7K]

Answer:

Hello,

Step-by-step explanation:

Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years since 1990. (a) what is the population expected to equal in year 2000 (b) determine the expression for the instantaneous rate of change in the population (c) what is the instantaneous rate of change in the population expected to equal in year 2000.

P(t)=125*e^{0.035*t}\\a)\\P(2000)=125*e^{0.035*(2000-1990)}=177.38...\\\\b)\\P'(t)=125*0.035*e^{0.035*t}\\\\c)\\\\P'(2000)=125*0.035*e^{0.035*(2000-1990)}=6.2084...

5 0
3 years ago
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