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3 years ago

How do I solve 300x300=

Mathematics

1 answer:

UNO [17]3 years ago

5 0

Answer:

its 90,000

Step-by-step explanation:

just put the zeros together then multiply 3x3

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Use the drawing tool(s) to form the correct answers on the provided graph. In the given equation, y is a function of x. Graph th

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Answer:

Here is the graph of y is a function of x.

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3 years ago

A moving company is called into a building and asked to relocate 520 bricks to a location 15 meters above the ground. If each br

Harman [31]

The answer seems to be B. atleast I am 90 percent sure

7 0

3 years ago

Read 2 more answers

To divide 14 2/3 divide by 2 3/4, Erik multiplied 14 2/3 times 4/3. Explain Erik's error.

nignag [31]

Answer:

Erik should have divided 14 2/3 by 2 3/4, but instead he multiplied causing him to have a greater answer than 5 and 1/3

(give brainliest please)

5 0

3 years ago

A rectangle has a length of 12 yards less than 3 times its width. If the area of the rectangle is 135 square yards, find the len

Aleonysh [2.5K]

Answer:

The length is 15 yards

Step-by-step explanation:

Given

Represent the width with W and length with L: So

$Area = 135yd^2$

$L=3W - 12$

Required

Determine the length of the rectangle:

Area is calculated as thus:

$Area = L * W$

Substitute 3W - 12 for L and 135 for Area

$135= (3W - 12) * W$

$135= 3W^2 - 12W$

Reorder:

$3W^2 - 12W - 135= 0$

Divide through by 3

$W^2 - 4W - 45 = 0$

Expand:

$W^2 - 9W + 5W - 45 = 0$

$W(W - 9) + 5(W - 9) = 0$

$(W + 5)(W-9) = 0$

$W + 5 = 0$ or $W - 9 = 0$

$W = -5$ or $W = 9$

But width can't be negative

So:

$W = 9$

Recall that: $L=3W - 12$

$L = 3 * 9 - 12$

$L = 15$

<em>Hence, the length 15 yards</em>

4 0

3 years ago

What if the value of x? show all work

alina1380 [7]

For this case we can make use of the Pythagorean theorem.
We have then:
(root (117)) ^ 2 = x ^ 2 + 6 ^ 2
Clearing x we have:
x ^ 2 = (root (117)) ^ 2 - 6 ^ 2
Rewriting:
x = root (117-36)
x = root (81)
x = 9
Answer:
The value of x is given by:
x = 9 cm

4 0

3 years ago