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victus00 [196]
3 years ago
13

Laura bought a coat in January for ⅓ off the original price. What percent was taken off of the price of the coat?

Mathematics
2 answers:
frozen [14]3 years ago
5 0

Answer:

33%

Step-by-step explanation:

1) Make it a decimal: 1/3=0.33

2) Make it a percent (move it 2 spaces larger): 0.33=33%

kompoz [17]3 years ago
4 0

Answer:

0.33\%

Step-by-step explanation:

\frac{1}{3}  = 0.33 \\  \\ 0.33 \times 100\% = 0.33\%

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If it costs $475 for 40 people to go to a party, how much does each person pay
densk [106]

Answer:

12

Step-by-step explanation:

we would do 475 divided among 40

475/40=11.875

but we would not use 11.875 so let's make it 12$

8 0
3 years ago
Read 2 more answers
In the following diagram, points C, A, and B are collinear. Use complete sentences to describe the sum of and .
Maru [420]
<span>The sum of angles CAD and DAB is 180 degrees. This is because they are all on a straight line (because points CAB are colinear) and angles on a straight line add up to 180 degrees.</span>
5 0
3 years ago
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Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p
Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

0 0
3 years ago
Hi, guys whoever can help me with this question and give me the right answer, I will award brainliest. Please give answer fast.
kifflom [539]

Answer:

X= 65

Step-by-step explanation:

180°-50°=130 (Angles on a straight line)

2x=130 ( Corrresponding Angle)

X= 130÷ 2

= 65

Hope this helps.

4 0
3 years ago
Read 2 more answers
Divide.<br><br> (5/6)÷(−2/3)
SSSSS [86.1K]

Hii

The answer is - 1 1/4

Sorry if it incorrect

8 0
3 years ago
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