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Mathematics

1 answer:

Butoxors [25]3 years ago

6 0

Answer:

A.Now you have 30/40 and 28/40

B.So the answer is 3/4>7/10 >.

Step-by-step explanation:

First you need to get common denominators.

I will choose 40

3/4*10/10=30/40

7/10*4/4=28/40

A.Now you have 30/40 and 28/40

B.So the answer is 3/4>7/10 >.

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Suppose integral subscript 3 superscript 5 f (x )space d x equals 5 integral subscript 3 superscript 9 g (x )space d x equals 3

igomit [66]

Answer:

Step-by-step explanation:

First we need to find the integral from 3 to 5 of g(x).

$\int\limits^9_3 {g(x)} \, dx =\int\limits^5_3 {g(x)} \, dx +\int\limits^9_5 {g(x)} \, dx \\\\\int\limits^5_3 {g(x)} \, dx =\int\limits^9_3 {g(x)} \, dx -\int\limits^9_5 {g(x)} \, dx\\\\\int\limits^5_3 {g(x)} \, dx =3-4=-1$

Then the integral of interest is ...

$\int\limits^5_3 {(f(x)+2g(x))} \, dx =\int\limits^5_3 {f(x)} \, dx +2\int\limits^5_3 {g(x)} \, dx =5+2(-1)\\\\\boxed{\int^5_3 {(f(x)+2g(x))} \, dx =3}$