What is 4/5 of 2kg in grams

Mathematics

2 answers:

Sveta_85 [38]2 years ago

8 0

Answer: 1600g

Step-by-step explanation: (4 * 2kg) / 5 = 8/5kg

8/5kg = 1.6kg

1.6kg * (1000g / 1kg) = 1600g

Pavlova-9 [17]2 years ago

3 0

Answer:

1 3/5kg.

Step-by-step explanation:

So, to figure this out, lets go over what we know.

There is 2kg.

We need to find 4/5 of this.

A way you can think of this is 2kg*4/5. Or:

2*4/5

Remember, all whole numbers have a denominator of 1. So this is:

2/1*4/5

$\frac{2}{1} *\frac{4}{5}$

When doing multipaction, the numerator multipies hte numeraot, and the denominator multiplies the denominator.

So in the numerator, it will be 2 times 4:

2*4=8

And in the denominator, it will be 1 times 5:

1*5=5

So the answer is:

8/5

Hope this helps!

You might be interested in

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe

-Dominant- [34]

Answer: 0.0031

Step-by-step explanation:

Binomial distribution formula :-

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where P(x) is the probability of x successes in the n independent trials of the experiment and p is the probability of success.

Given : A binomial probability experiment is conducted with the given parameters.

$n=9,\ p=0.8,\ x\leq3$

Now, $P(x\leq3)=P(3)+P(2)+P(1)+P(0)$

$=^9C_3(0.8)^3(1-0.8)^{9-3}+^9C_2(0.8)^2(1-0.8)^{9-2}+^9C_1(0.8)^1(1-0.8)^{9-1}+^9C_0(0.8)^0(1-0.8)^9\\\\=\dfrac{9!}{3!6!}(0.8)^3(0.2)^6+\dfrac{9!}{2!7!}(0.8)^2(0.2)^7+\dfrac{9!}{1!8!}(0.8)(0.2)^8+\dfrac{9!}{0!9!}(0.2)^9=0.003066368\approx0.0031$