All categories

3 years ago

Can I get a check to see if these are right please?

Mathematics

1 answer:

Anestetic [448]3 years ago

3 0

The domain is all possible values for x.

Here we can see a parabola the goes sideways.

The vertex of the parabola is at (3,-1).

That means the domain is $x\geq 3$

Think about it this way, is there any point on the parabola that can have a x coordinate of 4?

The range of a function is all possible y values. Is seems that the parabola stretches infinitely up and down, meaning that all values of y are possible.

You might be interested in

What is the area of this triangle?<br><br> Enter your answer in the box.

Norma-Jean [14]

Answer:

i think 8cm is triangle area

Step-by-step explanation:

because i saw that 8cm on the side so I told 8cm the triangle.

3 0

2 years ago

17. ralph is 3 times as old as sarah. in 4 years ralph will only be twice as old as sara will be then. find ralph’s age now.

spin [16.1K]

Answer:

Sara is now 4, will be 8 in 4 years. Ralph is now 12, will be 16 in 4 years.

7 0

3 years ago

Mutiply 4y-4w^8-3y^5w^3

sukhopar [10]

Answer:

48y⁶w¹¹

Step-by-step explanation:

[-3y⁵][4y] → -12y⁶

[w³][-4w⁸] → -4w¹¹

______

48y⁶w¹¹

I am joyous to assist you anytime.

8 0

4 years ago

Pls explain how you figured out both questions

Mariana [72]

Answer:

A=0.125

B=0.125

Step-by-step explanation

for both you would divide 0.5 by 4. you would cut 0.125 off of each side, but two sides together would 0.25

6 0

3 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago