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2 years ago

Using the table below, find the mean and median of the set of data.

Mathematics

1 answer:

Slav-nsk [51]2 years ago

5 0

Using their concepts concept, we have that:

a) The mean of the data-set is of 81.6.

b) The median of the data-set is of 80.

The mean of a data-set is given by the <u>sum of all observations in the data-set divided by the number of observations</u>.

In this problem, there are 2 + 8 + 6 + 3 + 9 = 28 observations, hence the mean is:

M = (70 x 2 + 75 x 8 + 80 x 6 + 85 x 3 + 90 x 9)/28 = 81.6.

<h3>What is the median?</h3>

The median of a data-set is the 50th percentile, the value that separates the median in two halfs.

This data-set has an even number of elements, hence the median is the mean of the 14th and 15th elements, as 28/2 = 14. Both elements are 80, hence the median is of 80.

More can be learned about the mean and the median of a data-set brainly.com/question/13202035

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Use △XYZ, in which ∠X is a right angle and tanY=815.

Neporo4naja [7]

Answer:

8/17

Step-by-step explanation:

The correct and complete question is:

<em>Use △XYZ, in which ∠X is a right angle and tanY=8/15. What is the ratio for sinY?</em>

From definition:

tan(Y) = opposite/adjacent

From the graph and the question:

tan(Y) = XZ/XY = 8/15

Then:

XZ = 8 and XY = 15. Using pytaghorean theorem:

XZ² + XY² = YZ²

8² + 15² = YZ²

√289 = YZ

17 = YZ

From definition:

sin(Y) = opposite/hypotenuse

From the graph:

sin(Y) = XZ/YZ

sin(Y)= 8/17

8 0

3 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

3 years ago

70 POINTS HELP ME URGENT SHOW YOUR WORK

Feliz [49]

Answer:

x= the number of ride tickets

y= the total cost of admission plus how many ride tickets a person purchases

y= 1.25x + 9.5

It is a$1.25 per ticket for the rides at the fair, so it would be 1.25 multiplied by the amount of tickets that are purchased (x). Spencer bought 17 tickets, so 17x1.25= 21.25 and it says that he spent a total of $30.75 at the fair, so 30.75-21.25=9.5, so that means the cost of admission is $9.50.

Step-by-step explanation:

I hope this helps!

7 0

3 years ago

A man is on a diet and goes into a shop to buy some turkey slices. He is given 3 slices which together weigh 1/3 of a pound, but

Ghella [55]

The three slices are each approximately 1/9 pound in weight, and, since 2/9 is less than 1/4, he can eat 2 whole slices and be okay. If he wants to eat partial slices, then he could eat 2 1/4 slices, as each slice weighs 4/36 pounds, so 2 slices would equal 8/36 pounds, leaving 1/36 pound left over in his diet, which is a quarter of the third slice.

2.25

6 0

3 years ago

Graph the function. Then State the domain and range. Also increasing and decreasing

masha68 [24]

Answer:

See below, I will let graphing part to yourself.

Step-by-step explanation:

First function: domain: $[-9,\infty)$ , range: $(-\infty, -2]$ , decreasing