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ra1l [238]
2 years ago
5

Using the table below, find the mean and median of the set of data.

Mathematics
1 answer:
Slav-nsk [51]2 years ago
5 0

Using their concepts concept, we have that:

a) The mean of the data-set is of 81.6.

b) The median of the data-set is of 80.

<h3>What is the mean?</h3>

The mean of a data-set is given by the <u>sum of all observations in the data-set divided by the number of observations</u>.

In this problem, there are 2 + 8 + 6 + 3 + 9 = 28 observations, hence the mean is:

M = (70 x 2 + 75 x 8 + 80 x 6 + 85 x 3 + 90 x 9)/28 = 81.6.

<h3>What is the median?</h3>

The median of a data-set is the 50th percentile, the value that separates the median in two halfs.

This data-set has an even number of elements, hence the median is the mean of the 14th and 15th elements, as 28/2 = 14. Both elements are 80, hence the median is of 80.

More can be learned about the mean and the median of a data-set brainly.com/question/13202035

#SPJ1

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What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?
snow_tiger [21]

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

s34 = 6936/2

s34 = 3468 <=== the sum of the first 34 terms:

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3 years ago
I need to know the answer and how to solve it
almond37 [142]

Hey! The answer is in the attachment.

Source : Done from 'My Paint'

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Kisachek [45]

Answer:

13,784

Step-by-step explanation:

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What is 16/48 equivalent to?
liberstina [14]
\frac{16}{48}=\\\\\frac{16:2}{48:2}=\boxed{\frac{8}{24}}\\\\\frac{8:2}{24:2}=\boxed{\frac{4}{12}}\\\\\frac{4:2}{12:2}=\boxed{\frac{2}{6}}\\\\\frac{2:2}{6:2}=\boxed{\frac{1}{3}}\\\\\frac{1\cdot10}{3\cdot10}=\boxed{\frac{10}{30}}\\\vdots
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Step-by-step explanation:

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