Question

Find the mean, median, and mode(s) of the data. Do not round.

Answer 1

The Mean, Median and Mode of the given set of data ( 11, 12, 32, 43, 45, 48, 48, 48 ) are 35.875, 44 and 48 respectively.

What is Arithmetic mean?

Arithmetic mean is simply the average of a given set numbers. It is determined by dividing the sum of a given set number by their number of appearance.

Mean = Sum total of the number ÷ n

Where n is number of numbers

Given the sets;

• 48, 12, 11, 45, 48, 48, 43, 32
• n = 8

First, we arrange in ascending order.

11, 12, 32, 43, 45, 48, 48, 48

Mode

Mode is the number with the highest appearance

Number with highest appearance  or frequency is 48 ( 3 appearance )

Mode = 48

Median

Middle numbers fall between 43 and 45

Median = ( 43 + 48 ) / 2

Median = 88 / 2

Median = 44

Mean

We add the numbers

11 + 12 + 32 + 43 + 45 + 48 + 48 + 48 = 287

Mean = Sum total of the number ÷ n

Mean = 287 /  8

Mean = 35.875

Therefore, the Mean, Median and Mode of the given set of data ( 11, 12, 32, 43, 45, 48, 48, 48 ) are 35.875, 44 and 48 respectively.

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Answer 2

The mean , median and mode of the data are 35.875, 44 and 48

How to find mean , median and mode?

The mean, median and mode can be found as follows:

mean = sum of terms / number of terms

mean = 48 + 12 + 11 + 45 + 48 + 48 + 43 + 32 / 8

mean = 287 / 8 = 35.875

11, 12, 32, 43, 45, 48, 48, 48

The median is the centre number.

Hence,

median = 43 + 45 / 2 = 88 / 2 = 44

The mode is the number that appears most which is 48.

learn more on mean, median and mode here:brainly.com/question/9588526

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