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Ronch [10]
3 years ago
6

If you roll a die what is the probability of rolling a 2 or 6?

Mathematics
2 answers:
Goryan [66]3 years ago
7 0

Answer:

Step-by-step explanation: the answer is 1/3

Vinil7 [7]3 years ago
5 0

Answer:

\frac{2}{6}

Step-by-step explanation:

We have that, a die is rolled once.

As, the total outcomes can be 1, 2, 3, 4, 5, 6.

So, the probability to obtain 2 is \frac{1}{6} and the probability to obtain 6 is \frac{1}{6}.

Thus, the probability of rolling 2 or 6 after rolling a die once will be \frac{1}{6}+\frac{1}{6} i.e. \frac{2}{6}.

Hence, the probability of rolling a 2 or 6 is \frac{2}{6}.

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3 years ago
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Use the function below to find F(2).<br> F(t) = 2•1/2^3t
navik [9.2K]

Answer:

F(2)= \frac{1}{32}

Step-by-step explanation:

The given function is

F(t) = 2 \cdot \:  \frac{1}{{2}^{3t} }

To find F(2), we substitute t=2 into the function.

This means that wherever we see t, we put 2

F(2) = 2 \cdot \:  \frac{1}{{2}^{3 \times 2} }

We multiply the exponent in the denominator to get:

F(2) = 2 \cdot \:  \frac{1}{{2}^{6} }

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F(2) = 2 \cdot \:  \frac{1}{64}

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6 0
3 years ago
Joe heard from a reliable source that only 22% of people actually sleep 8 hours or more per night. You do a survey and find 58 o
Juliette [100K]

Answer:

95% Confidence interval:  (31.32%,47.04%)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 148

Number of people who sleep for 8 hours or longer, x = 58

\hat{p} = \dfrac{x}{n} = \dfrac{58}{148} = 0.3918

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.3918\pm 1.96(\sqrt{\dfrac{0.3918(1-0.3918)}{148}})\\\\ = 0.3918\pm 0.0786\\\\=(0.3132,0.4704)=(31.32\%,47.04\%)

(31.32%,47.04%)  is the required 95% confidence interval.

8 0
3 years ago
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It would be 3 cm by 4 cm because you just divide the number of feet by 4.
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3 years ago
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77julia77 [94]

Answer:

2nd Graph

Step-by-step explanation:

6 0
4 years ago
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